ch07_solutions

# 2 5 1 129 r onn c for the symmetrical design t plh t

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+ 2 5 - 1 = 1.29 R onn C For the symmetrical design, t PLH = t PHL and t P = t PHL 1ns = 1.29 10pF ( 29 W L n 25 x 10 - 6 ( 29 5 - 1 ( 29 W L n = 129 1 | W L p = 2.5 W L n = 323 1 t r = t f = 2 t PHL = 2 ns b ( 29 t PHL = R onn C ln 4 V H - V TN V H + V L - 1 + 2 V TN V H - V TN = R onn C ln 4 3.3 - 0.75 3.3 + 0  - 1 + 2 0.75 ( 29 3.3 - 0.75 = 1.39 R onn C For the symmetrical design, t PLH = t PHL and t P = t PHL 1ns = 1.39 10pF ( 29 W L n 25 x 10 - 6 ( 29 3.3 - 0.75 ( 29 W L n = 218 1 | W L p = 2.5 W L n = 545 1 t r = t f = 2 t PHL = 2 ns 7.27 a ( 29 t PHL = R onn C ln 4 V H - V TN V H + V L - 1 + 2 V TN V H - V TN = R onn C ln 4 2.5 - 0.6 2.5 + 0  - 1 + 2 0.6 ( 29 2.5 - 0.6 = 1.35 R onn C For the symmetrical design, t PLH = t PHL and t P = t PHL 0.4ns = 1.35 100fF ( 29 W L n 25 x 10 - 6 ( 29 2.5 - 0.6 ( 29 W L n = 7.11 1 | W L p = 2.5 W L n = 17.8 1

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