P L V L I L 0991 V1 mA 0991 mW Trial 2 P L V L I L 1985 V2 mA 3970 mW Trial 3 P

P l v l i l 0991 v1 ma 0991 mw trial 2 p l v l i l

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P L = V L I L = (0.991 V)(1 mA) = 0.991 mW Trial 2 : P L = V L I L = (1.985 V)(2 mA) = 3.970 mW Trial 3 : P L = V L I L = (2.974 V)(3 mA) = 8.922 mW Trial 4 : P L = V L I L = (3.962 V)(4 mA) = 15.848 mW Trial 5 : P L = V L I L = (5.949 V)(5 mA) = 24.750 mW
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Interpretation of Data : Before we determine the Load Power for each trial, we must observe first that the Load Voltage for each trial should not exceed their corresponding Voltage Source which is its ideal voltage for the circuit. As we observed, an increase in Voltage Source will also affect an increase in Load Voltage and Load Current thus applying the formula P L = V L I L , we may concluded that as Voltage Source increases , Load Power also Increases and Vice Versa. Conclusion: As we performed the experiment (Power Measurements), we learned that in measuring Load Voltage, it should not exceed its ideal voltage which is the Voltage Source. Load Current is also relatively proportional to the Voltage source as being measured. In addition, an increase in Voltage Source will also affect an increase in Load Voltage and Load Current. And lastly by applying the formula P L = V L I L , we concluded that as Voltage Source increases, Load Power also Increases and Vice Versa.
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  • Fall '17
  • load voltage

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