# Reflection over the x axis up show work for the

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Reflection over the x-axis:UpShow work for the second point here:Y=3(3-1)^2Y=3(2)^2Y=3(4)Y=12Second Point: (3,12)3.f(x) = 2(x+ 3)2– 4Vertex: (-3,-4)Domain:All realnumbersRange:Y-4Axis of Symmetry:x=-3Vertical stretch:YesVertical compression:NoneGraph:AReflection over the x-axis:UpShow work for the second point here:Y=2(-5+3)^2-4Y=2(-2)^2-4Second Point: (-5,4)
Y=2(4)-4Y=44.f(x) = -12(x– 1)2+ 4Vertex: (1,4)Domain:All realnumbersRange:Y4Axis of Symmetry:x=1Vertical stretch:YesVertical compression:YesGraph:GReflection over thex-axis:DownShow work for the second point here:Y= -12(-3-1)^2+4Y=12(-16)+4Y= -4Second Point: (-3,-4)Write the quadratic equation in vertex form.Identify the vertex, domain, range, andaxis of symmetry.Answer yes or no to whether there is a vertical stretch, verticalcompression, or reflection over the x-axis. Then, graph the function.
5.f(x) = 2x2– 4x –1Vertex Form:y =1(x-1)21 1/2Show work here writing the equation in vertex form:Vertex:1,-1.5Axis of Symmetry:x=1Reflection over the x-axis:UpDomain:All real numbersVertical Stretch:NoRange:Y-1.5Vertical Compression:NoShow work for the second point here:Y=1Second Point:Graph:
a
6.Write the equation of the quadratic function shown in vertex form.+2)222a
7.Use geogebra to find the solutions to the following system of equations.
y =-3(x -2)2+ 5y = 2x – 4Solutions:x =,Insert a picture of the graph below:8.Compare the graph of f(x) =12x2+ 4x + 6 shown below with a parabola with anavalue of-2 and a vertexof ( 3, 2).
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