Solution a MW 10 57 2 350 MW 900 350 350 3 E N N E P P P P b fissions 1004 8 n

Solution a mw 10 57 2 350 mw 900 350 350 3 e n n e p

This preview shows page 1 - 3 out of 3 pages.

Solution (a) MW 10 57 . 2 350 . 0 MW 900 ) 350 . 0 ( ) 350 . 0 ( 3 E N N E P P P P (b) fission/s 10 04 . 8 n MeV/fissio 200 J 10 1.60 MeV 1 W 10 571 . 2 fission 19 13 9 N E P n (c)  kg 991 g 10 91 . 9 10 6.02 mol 1 g/mol 04 . 235 s/y 10 16 . 3 /s 10 8.0357 5 23 7 19 m
Image of page 1
OpenStax College Physics Chapters 32-34 3. (33-19) (a) What is the uncertainty in the energy released in the decay of a 0 due to its short lifetime? (b) What fraction of the decay energy is this, noting that the decay mode is 0 (so that all the 0 mass is destroyed)? Solution (a) Using 4 h t E we can calculate the uncertainty in the energy, given the lifetime of the 0 from Table 33.2 : eV 9 . 3 J 10 60 . 1 eV 1 J 10 28 . 6 ) s 10 4 . 8 ( 4 s J 10 63 . 6 4 19 19 17 34 t h E (b) The fraction of the decay energy is determined by dividing this uncertainty in the energy by the rest mass energy of the 0 found in Table 33.2 : 8 2 2 6 2 10 9 . 2 eV 10 0 . 135 eV 9256 . 3 0 c c c m E 4. (33-37) (a) How much energy would be released if the proton did decay via the conjectured reaction e p 0 ? (b) Given that the 0 decays to two s and that the e will find an electron to annihilate, what total energy is ultimately produced in proton decay? (c) Why is this energy greater than the proton’s total mass (converted to energy)? Solution (a) The energy released from the reaction is determined by the change in the rest mass energies: 2 f 2 i 2 0 c m m m mc mc E e p Using Table 33.2 , we can then determine this difference in rest mass energies: MeV 803 MeV 8 802 MeV 511 0 MeV 0 135
Image of page 2
Image of page 3

You've reached the end of your free preview.

Want to read all 3 pages?

  • Fall '18
  • Afrifa
  • Energy, Mass, Mass–energy equivalence, OpenStax College Physics

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern

Stuck? We have tutors online 24/7 who can help you get unstuck.
A+ icon
Ask Expert Tutors You can ask You can ask You can ask (will expire )
Answers in as fast as 15 minutes
A+ icon
Ask Expert Tutors