Physics Lab Report.docx

# From platform edges place it in a middle of a compact

• Lab Report
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from platform edges, place it in a middle of a compact disk and measure them together; after receiving the total mass of both objects subtract the mass of the disk which will leave the mass of marble alone. Ultimately, estimating the mass of marble to be 5.7 g, disk 14 g, and penny 2.25 g. The next step, divide diameters of each object by 2 to find the radius in cm, which will be later used to calculate the volume in cubic centimeters (cm^3) by the following formulas. V = π r 2 h for disk and penny, and V = 4 π r 3 3 for marble. To estimate an exact volume of a disk which consists of two parts, first, calculate both inner and outer volumes, and then subtract inner portion from outer. As a result, the values should be approximately 10.945 c m 3 for the disk, 0.284 c m 3 for a penny, and 2.145 c m 3 for the marble. Lastly, calculate the density ( ρ ) of a compact disk, marble, and penny in grams per centimeters cube ( g / c m 3 ) by dividing the mass of each by the parallel volumes. Thus,

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producing this result, the density of disk 1.279 g / c m 3 , marble 2.657 g / c m 3 , and penny 7.923 g / c m 3 Data : Object Mass (grams) Diameter (cm) Thickness (cm) Penny 2.25 1.9 0.1 Compact Disk 14 Inner - 1.5 Outer - 11.9 0.1 Marble 5.7 1.6 Calculations : 1) Penny: ¿ d 2 = 1.9 2 = 0.95 cm V = π r 2 h = π ( 0.95 ) 2 ( 0.1 ) = 0.284 cm 3 ρ = V m = 0.284 2.25 = 7.923 g / cm 3 2) Compact Disk R = D 2 = 11.9 2 = 5.95 cm r = d 2 = 1.5 2 = 0.75 cm 5.95 ¿ ¿ OuterVolume = π R 2 h = π ¿ Inner Volume = π r 2 h = π ( 0.75 ) 2 ( 0.1 ) = 0.177 cm 3 Volumeof Compact disk = ¿ π R 2 h π r 2 h = 11.122 0.177 = 10.945 c m 3 ρ = V m = 10.945 14 = 1.279 g / cm 3
3) Marble: r = d 2 = 1.6 2 = 0.8 cm V = 4 π r 3 3 = 4 π ( 0.8 ) 3 3 = 2.145 c m 3 ρ = V m = 2.145 5.7 = 2.657 g / c m 3
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• Spring '15
• Centimetre gram second system of units, Vernier scale, vernier

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