c.
I
i
= 0
i
C
=
/0.2 ms
20 V
20 V
25 V
10 k
t
C
e
E
=
R
υ
−
⎡
⎤
−
−
−
⎣
⎦
Ω
=
2.5 mA
e
−
t
/0.2 ms
d.
17.
υ
C
=
V
i
+ (
V
f
−
V
i
)(1
−
e
−
t/RC
)
τ
=
RC
= (2 k
Ω
)(10
μ
F)
= 8 + (4
−
8)(1
−
e
−
t
/20 ms
)
= 20 ms
= 8
−
4(1
−
e
−
t
/20 ms
)
= 8
−
4 + 4
e
−
t
/20 ms
= 4 + 4
e
−
t
/20 ms
υ
C
=
4 V(1 +
e
−
t
/20 ms
)
18.
V
i
= 10 V,
V
f
= 2 V,
τ
=
RC
= (1 k
Ω
)(1000
μ
F) = 1 s
υ
C
=
V
i
+ (
V
f
−
V
i
)(1
−
e
−
t
/
τ
)
= 10 V + (2 V
−
10 V)(1
−
e
−
t
)
= 10
−
8(1
−
e
−
t
)
= 10
−
8 + 8
e
−
t
υ
C
=
2 V+ 8 V
e
−
t
19.
V
i
= 10 V,
I
i
= 0 A
Using the defined direction of
i
C
i
C
=
(10 V
2 V)
1 k
−
−
Ω
e
−
t
/
τ
τ
=
RC
= (1 k
Ω
)(1000
μ
F) = 1 s
i
C
=
8 V
1 k
t
e
−
−
Ω
and
i
C
=
−
8mA
e
−
t

338
CHAPTER 24
20.
τ
=
RC
= (5 k
Ω
)(0.04
μ
F) = 0.2 ms (throughout)
υ
C
=
E
(1
−
e
−
t
/
τ
) =
20 V(1
−
e
−
t
/0.2 ms
)
(Starting at
t
= 0 for each plot)
a.
T
=
1
1
500 Hz
=
f
= 2 ms
2
T
= 1 ms
5
τ
= 1 ms =
2
T
b.
T
=
1
1
100 Hz
=
f
= 10 ms
2
T
= 5 ms
5
τ
= 1 ms =
1
5
2
T
⎛
⎞
⎜
⎟
⎝
⎠
c.
T
=
1
1
5 Hz
=
f
= 0.2 ms
2
T
= 0.1 ms
5
τ
= 1 ms =
10
2
T
⎛
⎞
⎜
⎟
⎝
⎠
21.
The mathematical expression for
i
C
is the same for each frequency!
τ
=
RC
= (5 k
Ω
)(0.04
μ
F) = 0.2 ms
and
i
C
=
/0.2 ms
20 V
5 k
t
e
−
Ω
=
4 mA
e
−
t
/0.2 ms
a.
T
=
1
= 2 ms,
= 1 ms
500 Hz
2
T
5
τ
= 5(0.2 ms) = 1 ms =
2
T
b.
T
=
1
100 Hz
= 10 ms,
2
T
= 5 ms
5
τ
= 1 ms =
1
5
2
T
⎛
⎞
⎜
⎟
⎝
⎠
c.
T
=
1
5000 Hz
= 0.2 ms,
2
T
= 0.1 ms
5
τ
= 1 ms =
10
2
T
⎛
⎞
⎜
⎟
⎝
⎠

CHAPTER 24
339
22.
τ
= 0.2 ms as above
T
=
1
500 Hz
= 2 ms
5
τ
= 1 ms =
2
T
0
→
2
T
:
υ
C
= 20 V(1
−
e
−
t
/0.2 ms
)
2
T
→
T
:
V
i
= 20 V,
V
f
=
−
20 V
υ
C
=
V
i
+ (
V
f
−
V
i
)(1
−
e
−
t
/
τ
)
= 20 + (
−
20
−
20)(1
−
e
−
t
/0.2 ms
)
= 20
−
40(1
−
e
−
t
/0.2 ms
)
= 20
−
40 + 40
e
−
t
/0.2 ms
υ
C
=
−
20 V+ 40 V
e
−
t
/0.2 ms
T
→
3
2
T
:
V
i
=
−
20 V,
V
f
= +20 V
υ
C
=
V
i
+ (
V
f
−
V
i
)(1
−
e
−
t
/
τ
)
=
−
20 + (20
−
(
−
20))(1
−
e
−
t
/
τ
)
=
−
20 + 40(1
−
e
−
t
/
τ
)
=
−
20 + 40
−
40
e
−
t
/
τ
υ
C
=
20 V
−
40 V
e
−
t
/0.2 ms
23.
υ
C
=
V
i
+ (
V
f
−
V
i
)(1
−
e
−
t/RC
)
V
i
= 20 V,
V
f
= 20 V
υ
C
= 20 + (20
−
20)(1
−
e
−
t/RC
)
=
20 V
(for 0
→
2
T
)
For
2
T
→
T
,
υ
i
= 0 V and
υ
C
=
20 V
e
−
t/
τ
τ
=
RC
= 0.2 ms
with
2
T
= 1 ms and 5
τ
=
2
T
For
T
→
3
2
T
,
υ
i
= 20 V
υ
C
=
20 V(1
−
e
−
t
/
τ
)
For
3
2
T
→
2
T
,
υ
i
= 0 V
υ
C
=
20 V
e
−
t
/
τ

340
CHAPTER 24
24.
τ
=
RC
= 0.2 ms
5
τ
= 1 ms =
2
T
V
i
=
−
10 V,
V
f
= +20 V
0
→
2
T
:
υ
C
=
V
i
+ (
V
f
−
V
i
)(1
−
e
−
t
/
τ
)
=
−
10 + (20
−
(
−
10))(1
−
e
−
t
/
τ
)
=
−
10 + 30(1
−
e
−
t
/
τ
)
=
−
10 + 30
−
30
e
−
t
/
τ
υ
C
=
+20 V
−
30 V
e
−
t
/0.2 ms
2
T
→
T
:
V
i
= 20 V,
V
f
= 0 V
υ
C
=
20 V
e
−
t
/0.2 ms
25.
Z
p
:
X
C
=
1
1
2
2
(10 kHz)(3 pF)
=
fC
π
π
= 5.31 M
Ω
Z
p
=
(9 M
0
)(5.31 M
90 )
9 M
5.31 M
j
Ω ∠ °
Ω ∠ −
°
Ω −
Ω
= 4.573 M
Ω
∠−
59.5
°
Z
s
:
C
T
= 18 pF + 9 pF = 27 pF
X
C
=
1
1
2
2
(10 kHz)(27 pF)
T
=
fC
π
π
= 0.589 M
Ω
Z
s
=
(1M
0
)(0.589 M
90 )
1 M
0.589 M
j
Ω ∠ °
Ω ∠ −
°
Ω −
Ω
= 0.507 M
Ω
∠−
59.5
°
V
scope
=
(0.507 M
59.5
)(100 V
0 )
=
(0.257 M
0.437 M
) + (2.324 M
3.939 M
)
s
i
s
p
j
j
Ω ∠ −
°
∠ °
+
Ω −
Ω
Ω −
Ω
V
Z
Z
Z
=
6
6
50.7
10 V
59.5
5.07
10
59.5
×
∠ −
°
×
∠ −
°
=
10 V
∠
0
°
=
1
10
(100 V
∠
0
°
)
=
s
p
θ
θ
Z
Z
=
−
59.5
°
26.
Z
p
:
X
C
=
5
1
1
(10
rad/s)(3 pF)
=
C
ω
= 3.333 M
Ω
Z
p
=
(9 M
0
)(3.333 M
)
9 M
3.333 M
j
Ω ∠ °
Ω
Ω −
Ω
= 3.126 M
Ω
∠−
69.68
°
Z
s
:
X
C
=
5
1
1
(10
rad/s)(27 pF)
=
C
ω
= 0.370 M
Ω
Z
s
=
(1M
0
)(0.370 M
90 )
1 M
0.370 M
j
Ω ∠ °
Ω ∠ −
°
Ω −
Ω
= 0.347 M
Ω
∠−
69.68
°
✓
=
p
s
θ
θ
Z
Z

CHAPTER 24
341
V
scope
=
(0.347 M
69.68
)(100 V


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- Spring '14
- Yoing