Of the inequality is r c rearranging the inequality

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of the inequality isR.(c) Rearranging the inequality givesx22x1x22x+ 10(x1)20.As the square of a real number is alwayspositive or zero, the only solution occurswhen(x1)2= 0;that is, whenx= 1. So the solution setis{1}.17
Exercise Booklet 3Solution to Exercise 41Rearranging the inequality gives3x+ 7<203x13x+ 7203x1<0(3x+ 7)(3x1)3x1203x1<0(3x+ 7)(3x1)203x1<09x2+ 18x7203x1<09x2+ 18x273x1<0x2+ 2x33x1<0(x1)(x+ 3)3x1<0.A factor is equal to 0 whenx=3,x=13andx= 1.x(−∞,3)3(3,13)13(13,1)1(1,)x10+x+ 30+++++3x10+++(x1)×(x+ 3)/(3x1)0+0+The table shows that the solution set is(−∞,3)(13,1).18
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Term
Summer
Professor
NoProfessor
Tags
Topology, Order theory, Complex number

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