B can we assume equal variances was the levenes test

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b.Can we assume equal variances? (Was the Levene’s Test for Equality of Variance significant or not
c.Write up the results for the ANOVA and the Tukey procedure for Hypothesis One below:
Hypothesis Two Output:DescriptivesLoyalty
NMeanStd.DeviationStd.Error95% ConfidenceInterval for MeanMinMaxLowerBoundUpperBoundsingle parent3260.345.637.99758.3162.384864two parent no step-parents4261.813.583.55360.6962.935064two parent withstep-parent2658.778.3921.64655.3862.162864Total10060.555.880.58859.3861.722864Test of Homogeneity of VariancesLoyaltyLeveneStatisticdf1df2Sig.5.933297.004ANOVALoyaltySum ofSquaresDfMeanSquareFSig.BetweenGroups150.440275.2202.230.113WithinGroups3272.3109733.735Total3422.75099Multiple ComparisonsLoyaltyTukey HSD(I) Household yougrew up in(J) Householdyou grew up inMeanDifference (I-J)Std.ErrorSig.95% ConfidenceIntervalLowerBoundUpperBoundsingle parenttwo parent nostep-parents-1.4661.363.532-4.711.78two parent withstep-parent1.5751.534.562-2.085.22two parent no step-parentssingle parent1.4661.363.532-1.784.71two parent withstep-parent3.0401.449.096-.416.49two parent withstep-parentsingle parent-1.5751.534.562-5.222.08two parent nostep-parents-3.0401.449.096-6.49.41

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Term
Winter
Professor
John Felton
Tags
Statistics, Normal Distribution, Variance, Null hypothesis, emotional support

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