335 303 335 303 335 303 335 303 335 303 38561 964 5 1

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( 3.35) (3.03) (3.35) (3.03) (3.35) (3.03 ) ( 3.35) (3.03) ( 3.35 ) (3.03) =- 3.8561 =-.964. 5-1 4 n=5, Confidence=95%?, r=-.964, CVCC=.87834 Absolute of r is │r│= .964 and is greater than .87834 so a negative (because original r was negative) linear relation exists. x - =4.8, y - =10.8, S x =3.35, S y =3.03, r=-.964 Slope: m=r S y = -.964 3.03 =-.873 S x 3.35 Y intercept: b=y - -mx - =10.8-(-.873)(4.8)=14.99 Line Equation: y=mx+b y=-.873x+14.99
Exam 10 Exam Page 1 Find the value of X 2 for 13 degrees of freedom and an area of .100 in the right tail of the chi- square distribution.
Exam Page 2 Find the value of X 2 for 17 degrees of freedom and an area of .050 in the left tail of the chi- square distribution.
Exam Page 3 Find the value of X 2 values that separate the middle 80 % from the rest of the distribution for 17 degrees of freedom.
Exam Page 4 Find the critical value of F for DOF=(6,18) and area in the right tail of .01.
Exam Page 5
The mayor of a large city claims that 30 % of the families in the city earn more than \$ 100,000 per year; 52 % earn between \$ 30,000 and \$ 100,000 (inclusive); 18 % earn less than \$ 30,000 per year. In order to test the mayor’s claim, 285 families from the city are surveyed and it is found that: 90 of the families earn more than \$ 100,000 per year; 135 of the families earn between \$ 30,000 and \$ 100,000 per year (inclusive); 60 of the families earn less \$ 30,000. Test the mayor’s claim based on 5 % significance level.
Exam Page 6 A trucking company wants to find out if their drivers are still alert after driving long hours. So, they give a test for alertness to two groups of drivers. They give the test to 475 drivers who have just finished driving 4 hours or less and they give the test to 635 drivers who have just finished driving 8 hours or more. The results of the tests are given below. Passed Failed Drove 4 hours or less 365 110 Drove 8 hours or more 440 195 Is there is a relationship between hours of driving and alertness? (Do a test for independence.) Test at the .5 % level of significance.