5.15/15 points | Previous AnswersPremiseThe diagram below is a schematic of the experimental setup. Note: Motion to the right (+x) and motionin the downward ydirection are taken as positive in this lab.Part (a)What is the applied force that sets the two masses in motion?Part (b)What is the expression for the net force Fnet1acting on mass m1? (Use the following as necessary: m1, T.)g,

a

g

Fnet1,y=Part (c)What is the expression for the net force Fnet2acting on mass m2? (Use the following as necessary: f, m2, Tand FNFg,.)

Part (d)Consider the vertical motion of mass m1. In part (b), you wrote down the net force acting on the mass.This is the left hand side of the equation for Newton's Second Law (Fnet= ma) and this net force equalsm1a. Similarly, for the horizontal motion of mass m2the left hand side of the equation for Newton'sSecond Law is the net horizontal force and the right hand side is m2aBased on the above explanation and your answers in parts (b) and (c), what is the expression for theacceleration aof the two masses? Eliminate Tand give your answers in terms of m1, m2, g, and f.only.

You have completed the problem!Additional MaterialsNewton's Second LawAppendix

6.5/5 points | Previous AnswersIn this lab you will fit your data to a straight line. Which variables will be kept constant? (Select all thatapply.)