Cw as the current in the wire increases the flux is

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CW; as the current in the wire increases the flux is increased in direction towards the plane 23.39 The figure shows a zero-resistance rod sliding to the right on two zero-resistance rails separated by the distance = 0.363 . The rails are connected by a 11.8 resistor, and the entire system is in a uniform magnetic field with a magnitude of 0.850 . Find the force that must be exerted on the rod to maintain a constant current of 0.168 in the resistor. F = B I L = 0.850 T* 0.168 A * 0.363 m = 51.8 mN What is the rate of energy dissipation in the resistor? Power: P = I 2 R = (0.168) 2 * 11.8 = 0.333 W = 0.333 W What is the mechanical power delivered to the rod? Mechanical Power: P = F * v = I 2 R = 0.333 W
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= 0.333 W Motional EMF in a Conducting Rod In the figure, a conducting rod of length = 31.0 moves in a magnetic field of magnitude 0.540 directed into the plane of the figure. The rod moves with speed = 5.00 in the direction shown. When the charges in the rod are in equilibrium, which point, a or b, has an excess of positive charge? B The force on a charge moving with velocity in a magnetic field is given by . The magnitude of the force is given by where is the magnitude of the charge, and are the magnitudes of the velocity and magnetic field and is the angle measured from the direction of to the direction of . When is perpendicular to , and . You can use the right-hand rule to determine the direction in which the electrons in the rod are forced to move. What is the direction of the electric field in the rod? B A Keep in mind that the electric field exists due to the separation of the positive and negative charges caused by the magnetic force. Also, recall that electric field lines start on positive charges and end on negative charges. When the charges in the rod are in equilibrium, what is the magnitude of the electric field within the rod? E = F / q = v x B =
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= 2.7 V/m Which point, a or b, has a higher potential? B What is the magnitude of the potential di ff erence between the ends of the rod? V = W / q = F L / q = E L = v B L = 5 * .54 * .31 = .837V = 0.837 V What is the magnitude of the motional emf induced in the rod?
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  • Spring '12
  • Griffith
  • Physics, Work, Magnetic Field, Faraday's law of induction, conducting rod

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