11-17-11 Sinusoidal Response of RC and RL Circuits

Question 1 is this a high pass filter or a low pass

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Question 1. Is this a high-pass filter or a low-pass filter? This circuit is a high-pass filter as the output voltage gets closer to the input voltage as the frequency rises. Question 2. At approximately which frequency would be the half-power point? The half power occurs when . Matching this with the equation for frequency, , we can find the frequency:
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II. RL Circuit This portion was very similar to the previous, except we used a 1000μH inductor instead of a capacitor. As such, the same basic format will be used. Figure 4. The RL circuit for part 1. Figure 5. The graph from the oscilloscope in the lab, at a frequency of approximately 80kHz Table 3. The values of the measured with the real oscilloscope. Frequency Input Voltage () Output Voltage () Output Voltage () V-I Time Difference () Phase Shift () Resistor Current () 800 Hz 10 V 9.60 V 3.16 V 20 μs 5.6 31.6 mA 8 kHz 10 V 9.00 V 2.90 V 14 μs 40.32 29.0 mA 80 kHz 10 V 1.60 V 0.518 V 2.8 μs 80.64 5.18 mA 500 kHz 10 V 0.136 V 0.048 V 560 ns 100.8 0.481 mA Table 4. The calculated values of the above. Frequency Output Voltage () Output Voltage () V-I Time Difference () Phase Shift () Resistor Current () 800 Hz 9.521 V 3.366 V 6.66 μs 1.919282 33.66 mA 8 kHz 6.654 V 2.352 V 6.432 μs 18.52617 23.52 mA 80 kHz 1.659 V 0.5866 V 2.548 μs 73.38408 5.866 mA 500 kHz 0.3084 V 0.1091 V 484 ns 87.2664 1.090 mA Similar to the previous procedure, for these calculated values, our error increased as the frequency did, due to the lack of precision.
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Question 3. Is this a high-pass filter or a low-pass filter? This circuit is a low-pass filter as the output voltage gets farther from the input voltage as the frequency rises.
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