11-17-11 Sinusoidal Response of RC and RL Circuits

# Question 1 is this a high pass filter or a low pass

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Question 1. Is this a high-pass filter or a low-pass filter? This circuit is a high-pass filter as the output voltage gets closer to the input voltage as the frequency rises. Question 2. At approximately which frequency would be the half-power point? The half power occurs when . Matching this with the equation for frequency, , we can find the frequency:

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II. RL Circuit This portion was very similar to the previous, except we used a 1000μH inductor instead of a capacitor. As such, the same basic format will be used. Figure 4. The RL circuit for part 1. Figure 5. The graph from the oscilloscope in the lab, at a frequency of approximately 80kHz Table 3. The values of the measured with the real oscilloscope. Frequency Input Voltage () Output Voltage () Output Voltage () V-I Time Difference () Phase Shift () Resistor Current () 800 Hz 10 V 9.60 V 3.16 V 20 μs 5.6 31.6 mA 8 kHz 10 V 9.00 V 2.90 V 14 μs 40.32 29.0 mA 80 kHz 10 V 1.60 V 0.518 V 2.8 μs 80.64 5.18 mA 500 kHz 10 V 0.136 V 0.048 V 560 ns 100.8 0.481 mA Table 4. The calculated values of the above. Frequency Output Voltage () Output Voltage () V-I Time Difference () Phase Shift () Resistor Current () 800 Hz 9.521 V 3.366 V 6.66 μs 1.919282 33.66 mA 8 kHz 6.654 V 2.352 V 6.432 μs 18.52617 23.52 mA 80 kHz 1.659 V 0.5866 V 2.548 μs 73.38408 5.866 mA 500 kHz 0.3084 V 0.1091 V 484 ns 87.2664 1.090 mA Similar to the previous procedure, for these calculated values, our error increased as the frequency did, due to the lack of precision.
Question 3. Is this a high-pass filter or a low-pass filter? This circuit is a low-pass filter as the output voltage gets farther from the input voltage as the frequency rises.
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