Pset 1 Solution 1. The current through the shunt resistor is
I= V2 = = 0.5 A . R4
The same through the 40 Ohm resistor is the same. Therefore, the voltage of the DC source is V s = I (40 + 4) = 22V . If the shunt is absent, the current would have been
I0
Pset 1 Solution
1. The current through the shunt resistor is
I=
V 2
= = 0.5 A .
R 4
The same through the 40 Ohm resistor is the same. Therefore, the voltage of the DC source is
V s = I (40 + 4) = 22V .
If the shunt is absent, the current would have been
I
MAE 3800 Instrumentation and Measurements Laboratory
Problem Set #2 Due: Tuesday, March 16 Problem 1 (10 points) (Prob. 3.22 of the textbook) The manufacturer of inexpensive outdoor thermometers checks a sample of nine against a 68 o F standard. The follo
MAE 3800 SP10 Exam #1 Student Name: 3%.“ \é,g:>t‘x~-» (3% “Y to";
Problem 1. (12 pts) A DC Power Source drives a resistive heater as shown below A digital multimeter is used to take
measurements.
3 Resistive
o Heater
+
DC Power
Source
UNIVERSITY OF MISSOURI - COLUMBIA DEPARTMENT OF MECHANICAL AND AEROSPACE ENGINEERING MAE 3800 Instrumentation and Measurements Laboratory Problem Set #4 Due: Tuesday, April 27
Problem 1 (10 points) (Prob. 6.1 of the textbook) Consider an inductive displac
MAE 3800 Instrumentation and Measurements Laboratory
Problem Set #3 Due: Tuesday, April 6
Problem 1 (10 points) (Problem 12.1 from the textbook) A simple tension member with a diameter of 0.505 in. is subjected to an axial force of 7215 lbf. Strains of 16
MAE 3800 Instrumentation and Measurements Laboratory
Problem Set #1 Due: Tuesday, February 23 Problem 1 (10 points) One method to measure the current passing through a load is by inserting a shunt resistor with known resistance into the circuit and measur
1. (4.3) This function is an odd function.
An = 0
2 T /2
2 T
2 T /2
T
Bn = T / 2 y (t ) sin( nt )dt = 0 y (t ) sin(nt )dt = [ 0 y (t ) sin(nt )dt + T / 2 y (t ) sin(nt )dt ]
T
T
T
2 T /2
2 F
T
= [ 0 F sin(nt )dt + T / 2 ( F ) sin(nt )dt ] = ( )[ cos(nt )
1. (6.1) Note the units associated with the equation (6.3c).
a
(0.25 / 2) 2 2.54 2
10 8 = 3.142 10 4 (H)
L = 1.26n 2 a 10 8 = 1.26 100 2
0.05 2.54
ha
L
ei
eo =
2
R + (L) 2
Sensitivity is given by
eo eo L
=
L ha
ha
a
eo
L
L
R 2
= 1.26n 2 ( a2 ) 10 8 =
wh
9/28/2016
MAE 3800 Instrumentation and
Measurements Laboratory
Lecturer: Prof. Frank Feng
Teaching Assistants:
Pre-requisites:
Co-requisite:
Gerhard Schnieders
Siddharth Penmetcha
Benjamin Davis
Allison Cole
Consider graduate school , dual enrollment, und
New York City crane collapse leaves 1 dead, 3 injured
By Ray Sanchez, CNN
Updated 2:37 PM ET, Fri February 5, 2016 | Video Source: CNN
741 OpAmp
(DC+)
(DC-)
Pin numbering starts from the dot (or left of
the notch) in counter clockwise direction
DC Power S
Bias Error and Precision Error
Sample Average:
The picture can't be display ed.
How to calculate bias error
From the Specifications in the meter manual
Example: Meter reads 6.554V. Assume 1 year calibration cycle.
Accuracy = 6.554*0.025%+ 2 (0.001)=0.004
Digital
Multimeter
(DMM)
AC-DC: Full wave rectifier
Valves for electrons
No current flows in a reversely-biased
diode:
Check valve analogy
Crystal diode: 1876
Transistors
Operational Amplifier
741 OpAmp
741 OpAmp
(DC+)
(DC-)
Pin numbering starts from th
October 13, 2016
To: Prof. Frank Feng
From:
Subject: Calibration of a Distance Sensor
Introduction
In potential robotics applications, there is a need for distance sensors that give accurate and
reliable results. With simpler applications, there is also a
Sources of errors
Loading error seen in Lab 2
Saturation
Sources of Error
DC+
DC-
Saturation - Overload
d
d
F
Hysteresis for a tensile specimen
Hysteresis is the path dependent response. More common in
mechanical systems.
Micrometer
Hysteresis
Spring Str
A
5k
2V(p- p)
Two equal resistors divide voltage into
two equal parts
If the total is 2V (peak-to-peak), the
voltage over each resistor is 1V (p-p)
B
5k
C
VAB 1V(p- p)
VBC 1V(p- p)
VAC 2V(p- p)
This connection would work if the
two channels are unrelated
d 2
1. A =
4
= .2003in 2 , a =
E=
Fa
= 36.02 10 3 psi
A
a
= 21.96 10 6 psi , = L = .296
a
a
2. M = 50 10 = 500in lbf .
=
My 6 M
6 500
= 3556 psi
= 2 =
I
wt
1.5 .75 2
1 =
= 119.7 strain
E
2 = 1
Since the two gages are in adjacent arms,
e
F
F
| o |= | 1 2
Instrumentation in Mechanical Engineering
Jeremy McCoy
Instruments and measurements, like fluids or heat transfer is an essential class in a
mechanical engineering curriculum. Outside the classroom, I have seen this classs importance
in my two internships
Date:
10/13/2016
To:
Benjamin Davis
From:
Jeremy McCoy
Subject: Calibration of a distance sensor
Objective
For this experiment we are testing the suitability of a GP2Y0A02YKOF sensor at different
distances. Along with changes the distance, the effect targ
UNIVERSITY OF MISSOURI - COLUMBIA
DEPARTMENT OF MECHANICAL AND AEROSPACE ENGINEERING
MAE 3800 Instrumentation and Measurements Laboratory
EXPERIMENT #5 Design and implementation of a pressure measurement system for soda cans.
Due: Thursday, March 24
Pre-l
UNIVERSITY OF MISSOURI - COLUMBIA
DEPARTMENT OF MECHANICAL AND AEROSPACE ENGINEERING
MAE 3800 Instrumentation and Measurements Laboratory
EXPERIMENT #3 Operational Amplifier
Due: Tuesday, February 16
1 Introduction:
Almost all sensors convert physical qua
UNIVERSITY OF MISSOURI - COLUMBIA
DEPARTMENT OF MECHANICAL AND AEROSPACE ENGINEERING
MAE 3800 Instrumentation and Measurements Laboratory
Spring 2016
EXPERIMENT #1 Resistance, Voltage, and Current measurement: Estimation of temperature of the tungsten fil
Instrument and Measurements Lab Design Project
December 7th, 2007
Tyler Mentel (33.33%) Matt Ponzer (33.33%) Brian Stephens (33.33%)
Abstract: The purpose of this project is to design a system for US Border Patrol that can be used to detect illegal immigr
Digital
Multimeter
(DMM)
AC-DC: Full wave rectifier
Valves for electrons
No current flows in a reversely-biased
diode:
Check valve analogy
Crystal diode: 1876
Transistors
741 OpAmp
Operational Amplifier
741 OpAmp
(DC+)
(DC-)
Pin numbering starts from th
Pset 1 Solution
1. The current through the shunt resistor is
I
V 2
0.5 A .
R 4
The same through the 40 Ohm resistor is the same. Therefore, the voltage of the DC source is
V s I (40 4) 22V .
If the shunt is absent, the current would have been
I0
Vs
0.5
Lab 7
Open Ended Design project
Date: December 9, 2016
To: Benjamin Davis
From:
Matthew Perry
Jeremy McCoy
Nurhidayatun Najwa Anuar
ABSTRACT
The purpose of this design project is to analyze if a piezoelectric sensor could be used to detect
illegal immigra
Date:
10/13/2016
To:
Benjamin Davis
From:
Jeremy McCoy
Subject: Measuring Pressure on Soda Cans
Summary
The soda company, SodaCorp, has had issues with soda cans spontaneously popping open. To
help solve this problem we have been tasked to measure the pre
Date:
11/17/2016
To:
Benjamin Davis
From:
Jeremy McCoy
Subject: Braking Force of an Eddy Current
Objective
An Eddy current brake, unlike conventional frictional braking uses a magnetic force from a
magnet passing over a conductive surface. This force is p