BROWARD COLLEGE
Course Syllabus
HFT 2250 Hotel Management
Spring 2016
Reference number
Campus and Room
Day and Time:
Instructor:
Office:
Telephone:
E-mail Address:
Office Hours:
510197
Central Campus, Rm # 9/107
Mondays 6:30pm-9:15pm
Prof. Robert Donato
9
Ariel Lue
Maria Sanchez
Alberto
April 12th, 2015
HTF
Paris
For our destination we choose Paris. Paris is mostly known as a beautiful and
romantic place with great sceneries. A nonstop flight from Miami, Florida to Paris,
France averages to about 10 hours
Alberto Nunez
HFT 2220
July 1, 2015
Human Resources Homework
Case Study Page 167
Dimension: Strategy
1. Is it important that Stacey do what is necessary to ensure that quality and quantity
standards can be attained before these new procedures are put in p
Alberto Nunez
HFT 2220
May 26, 2015
Human Resources Homework
Case Study #1 Page 17
Dimension: Strategy
1. How are the results of strategies used to manage HR at Felixs hotel affecting the
business?
2. What are possible reasons that top-level managers at F
Alberto Nunez
HFT 2220
July 20, 2015
HR Homework
Case Study #5 Page 234
Dimension: Employee Protection
1. What evidence is there of a hostile work environment in this case?
Angela is getting sexually harassed by Roger Sheets.
2. What evidence is there of
Construct a finite-state machine for a
toll machine that opens a gate after 25
cents, in nickels, dimes, or quarters,
has been deposited. No change is given
for overpayment, and no credit is given
to the next driver when more than 25
cents has been deposi
machine is shown in Figure 5.
EXAMPLE 7 In a certain coding scheme,
when three consecutive 1s appear in a
message, the receiver of the message
knows that there has been a
transmission error. Construct a finitestate machine that gives a 1 as its
current o
symbols read so far is divisible by 3
and an output of 0 otherwise. P1: 1
CH13-7T Rosen-2311T MHIA017Rosen-v5.cls May 13, 2011 10:27 13.3
Finite-State Machines with No Output
865 17. Construct a finite-state
machine that determines whether the
input strin
state machine in Figure 3 if the input
string is 101011. Solution: The output
obtained is 001000. The successive
states and outputs are shown in Table
4. We can now look at some
examples of useful finite-state
machines. Examples 5, 6, and 7
illustrate tha
finite-state machine with output,
where the output is determined only
by the state. This type of finite-state
machine is known as a Moore machine,
because E. F. Moore introduced this
type of machine in 1956. Moore
machines are considered in a sequence
of
s0,F) if it takes the initial state s0 to a
final state, that is, f (s0, x) is a state in F.
The language recognized or accepted
by the machine M, denoted by L(M), is
the set of all strings that are
recognized by M. Two finite-state
automata are called eq
arbitrarily many strings from A. That
is, A = k=0 Ak. EXAMPLE 3 What
are the Kleene closures of the sets A =
cfw_0, B = cfw_0, 1, and C = cfw_11? Solution:
The Kleene closure of A is the
concatenation of the string 0 with itself
an arbitrary finite number
other coins) or a quarter and a nickel
(and any number of other coins) have
been inserted. Once the door can be
opened, the customer opens it and
takes a paper, closing the door. No
change is ever returned no matter how
much extra money has been inserted.
Finite-State Machines with No Output
Introduction One of the most
important applications of finite-state
machines is in language recognition.
This application plays a fundamental
role in the design and construction of
compilers for programming languages.
can be modeled using a structure
called a finite-state machine. Several
types of finite-state machines are
commonly used in models. All these
versions of finite-state machines
include a finite set of states, with a
designated starting state, an input
alph
return w else return substr(w, n,
n)reverse (substr (w, 1, n 1)
cfw_substr(w, a, b) is the substring of w
consisting of the symbols in the ath
through bth positions 39. The
procedure correctly gives the reversal
of as (basis step), and because the
reversa
theory of recursive functions,
investigating questions of
computability and decidability, and
proved one of the central results of
automata theory. He served as the
Acting Director of the Mathematics
Research Center and as Dean of the
College of Letters a
and the output for that transition.
Figure 1 shows such a directed graph
for the vending machine. Finite-State
Machines with Outputs We will now
give the formal definition of a finitestate machine with output.
DEFINITION 1 A finite-state machine M
= (S, I
1,0 1,0 s0 s2 s3 s1 b) Start s0 s1 s2 1,0
0,0 1,1 1,0 0,0 0,1 c) Start s0 s2 s3 s1
0,0 1,1 1,1 0,0 0,0 0,0 1,1 1,0 3. Find the
output generated from the input string
01110 for the finite-state machine with
the state table in a) Exercise 1(a). b)
Exercise
Gives an Output of 1 If and Only If the
Input String Read So Far Ends with
111. is read is 1, because this
combination of input and state shows
that three consecutive 1s have been
read. All other outputs are 0. The state
diagram of this machine is shown i
state machine with S = cfw_s0, s1, s2, s3, I
= cfw_0, 1, and O = cfw_0, 1. The values of the
transition function f are displayed in
the first two columns, and the values of
the output function g are displayed in
the last two columns. Another way
to repres
TABLE 3 f g Input Input State 0 1 0 1 s0
s1 s3 1 0 s1 s1 s2 1 1 s2 s3 s4 0 0 s3 s1
s0 0 0 s4 s3 s4 0 0 An input string takes
the starting state through a sequence
of states, as determined by the
transition function. As we read the
input string symbol by s
the orange button (O), and the red
button (R). The possible outputs are
nothing (n), 5 cents, 10 cents, 15 cents,
20 cents, 25 cents, an orange juice, and
an apple juice. We illustrate how this
model of the machine works with this
example. Suppose that a
Machine. Next State Output Input Input
State 5 10 25 O R 5 10 25 O R s0 s1 s2
s5 s0 s0 nn n n n s1 s2 s3 s6 s1 s1 nn n
n n s2 s3 s4 s6 s2 s2 n n 5 n n s3 s4 s5
s6 s3 s3 n n 10 n n s4 s5 s6 s6 s4 s4 n n
15 n n s5 s6 s6 s6 s5 s5 n 5 20 n n s6 s6
s6 s6 s0 s0
integer n. Basis step: P (1) is obviously
true. Inductive step: Assume that P (k)
is true. Then cos(k+1)x)+i sin(k+1)x)
= cos(kx+x)+i sin(kx+x) = cos kx cos x
sin kx sin x + i(sin kx cos x + cos kx sin x)
= cos x(cos kx + i sin kx)(cos x + i sin x) =
(co
As Example 8 shows, a finite-state
automaton may have more states than
one equivalent to it. In fact, algorithms
used to construct finite-state automata
to recognize certain languages may
have many more states than necessary.
Using unnecessarily large fi
follows a 0 in the string (before we
encounter two consecutive 0s), we
return to s0 and begin looking for
consecutive 0s all over again. The
reader should verify that the finitestate automaton in Figure 3(b)
recognizes the set of bit strings that
contain
respectively. The reader should verify
that the finite-state automaton in
Figure 3(e) recognizes the set of bit
strings that contain two 0s.
EXAMPLE 7 Construct a deterministic
finite-state automaton that recognizes
the set of bit strings that contain an