Homework G:
Due Friday April 18, 2014 at conference
Instructions: Please provide a brief verbal explanation of each step in your solution. State
where the formulas are coming from, and why they are applicable here. Use symbols and
formulae eectively denin
Homework F:
Due Tuesday April 8, 2014 at lecture
(Hand it in on Friday April 4 at conference if you can)
Instructions: Please provide a brief verbal explanation of each step in your solution. State
where the formulas are coming from, and why they are appl
Homework A: Due Friday, Feb 7, 2014 at conference.
Instructions: Please provide a brief verbal explanation of each step in your solution. State
where the formulas are coming from, and why they are applicable here. Use symbols and
formulae eectively dening
1. Using the given conversion factors, we find (a) the distance d in rods to be d = 4.0 furlongs =
( 4.0 furlongs )( 201.168 m furlong )
5.0292 m rod
= 160 rods,
(b) and that distance in chains to be d =
( 4.0 furlongs )( 201.168 m furlong )
20.117 m chai
1. Conservation of momentum requires that the gamma ray particles move in opposite directions with momenta of the same magnitude. Since the magnitude p of the momentum of a gamma ray particle is related to its energy by p = E/c, the particles have the sam
1. If R is the fission rate, then the power output is P = RQ, where Q is the energy released in each fission event. Hence, R = P/Q = (1.0 W)/(200 106 eV)(1.60 10 19 J/eV) = 3.1 1010 fissions/s.
2. We note that the sum of superscripts (mass numbers A) must
1. Our calculation is similar to that shown in Sample Problem 421. We set K = 5.30 MeV=U = (1/ 4 0 )( q qCu / rmin ) and solve for the closest separation, rmin:
rmin
19 9 q qCu kq qCu ( 2e )( 29 ) (1.60 10 C )( 8.99 10 V m/C ) = = = 4 0 K 4 0 K 5.30 106
1. The number of atoms per unit volume is given by n = d / M , where d is the mass density of copper and M is the mass of a single copper atom. Since each atom contributes one conduction electron, n is also the number of conduction electrons per unit volu
1. (a) For a given value of the principal quantum number n, the orbital quantum number ranges from 0 to n 1. For n = 3, there are three possible values: 0, 1, and 2. (b) For a given value of , the magnetic quantum number m ranges from  to + . For = 1 , t
1. According to Eq. 394 En L 2. As a consequence, the new energy level E'n satisfies
En L = En L
FG IJ = FG L IJ H K H L K
2
2
=
1 , 2
which gives L = 2 L. Thus, the ratio is L / L = 2 = 1.41.
2. (a) The groundstate energy is
( 6.63 10 J s ) h2 E1 = n2
1. (a) Let E = 1240 eVnm/min = 0.6 eV to get = 2.1 103 nm = 2.1 m. (b) It is in the infrared region.
2. The energy of a photon is given by E = hf, where h is the Planck constant and f is the frequency. The wavelength is related to the frequency by f = c,
1. From the time dilation equation t = t0 (where t0 is the proper time interval,
= 1 / 1  2 , and = v/c), we obtain
= 1
FG t IJ . H t K
2 0
The proper time interval is measured by a clock at rest relative to the muon. Specifically, t0 = 2.2000 s. We a
1. (a) The flux through the top is +(0.30 T)r2 where r = 0.020 m. The flux through the bottom is +0.70 mWb as given in the problem statement. Since the net flux must be zero then the flux through the sides must be negative and exactly cancel the total of
1. (a) The magnitude of the magnetic field due to the current in the wire, at a point a distance r from the wire, is given by
B=
0i
2r
.
With r = 20 ft = 6.10 m, we have
c4 10 B=
hb 2 b6.10 mg
7
T m A 100 A
g = 3.3 10
6
T = 3.3 T.
(b) This is about one
Homework B: Due Friday, Feb 14, 2014 at conference.
Instructions: Please provide a brief verbal explanation of each step in your solution. State
where the formulas are coming from, and why they are applicable here. Use symbols and
formulae eectively denin
Homework H:
Due Friday April 25, 2014 at conference
Instructions: Please provide a brief verbal explanation of each step in your solution. State
where the formulas are coming from, and why they are applicable here. Use symbols and
formulae eectively denin
f"
t4 3;
PWa
Cr,*"a
& sphetm[
*hnc,rn*k
11.
'rba;'(or,
I
*" L u a 4s f
ab gr!?r b! "&! . m d.e(*!'., sa, *
I + l,rn .
+TL. dce.eat"fr
l+ *=4
z
J
ff_r
t\ocfw_e+s<,
b* f:p
t
=Z*
cfw_,*, o
Ps
=lf
zD
?*
.@
qri"i*
]

I
=r'm:ffi
,31,i+g
Fo,
Sehe';oo
Hw 13 a
Lin Yang
May 6, 2012
Note: I used a function Int() to get the integer, wich means a oor integer.
For example
Int(10.9) = 10
Int(1.1) = 1
Chapter 36, Problem 8
This is a singleslit diraction. Accordin to the book, the diraction pattern on
the wall
Home Work 12
Lin Yang
May 5, 2012
Chapter 35, Problem 83:
For ray 1, the distance traveled by light is
l = 7d
The phase is
1
= nkl =
For ray 2, the distance traveled is
2
=
2 7d
n
2n 2d
Phase shift for out of phase is
=
1
2
=
2n 5d
=
Incert the value
)d=
Homework D: Due Friday, March 7, 2014 at conference.
Instructions: Please provide a brief verbal explanation of each step in your solution. State
where the formulas are coming from, and why they are applicable here. Use symbols and
formulae eectively deni
PHYS 2220 Fall 2013 Gauss Law (Default) September 2013
The next eight questions pertain to the situation described below.
A point charge q] = 7.9 uC is located at the center of a
thick conducting shell of inner radius a = 2.1 cm and outer
radius b = 4.9
Homework C: Due Friday, Feb 28, 2014 at conference.
Instructions: Please provide a brief verbal explanation of each step in your solution. State
where the formulas are coming from, and why they are applicable here. Use symbols and
formulae eectively denin