STATISTICS 664 Autumn 2010 Homework 6 (due Tuesday Nov. 16). 1. Suppose that after constructing x and R control charts in Problem 6.3, process engineers decided to change the subgroup size to n = 3. Give the center line and control limits for new charts b
STATISTICS 664 Autumn 2010 Homework 3 (due Tuesday Oct. 19). Read Chapter 5. Do the following problems 5.17 5.18 5.19 5.32 (In this problem you are simply being asked to compute the probability that if averages from m samples are plotted on the chart, tha
STATISTICS 664 Autumn 2010 Homework 2 (due Tuesday Oct. 5). Do the following problems. Use Minitab or JMP when possible. 3.12 3.25 3.31 3.32 3.36 3.37 3.45 3.46 3.47
STATISTICS 664 Autumn 2010 Homework 1 (due Tuesday September 28). Read chapters 1, 2, and 3. Do the following problems. Use Minitab or JMP when possible. 3.7 (just make the histogram) 3.17 3.19 3.20
Statistics 664 Autumn 2010 Homework 8 Solutions 1. Problem 7.2 Here is the fraction noncomforming chart (P-chart) for all the data from Minitab.
PCha r t of Ex 7 2 N um
0.10 0.08
1 1
Pr opor t ion
0.06 0.04 0.02 0.00 1 3 5 7 9 11 Sa mple 13 15 17 19
UCL=
Statistics 664 Autumn 2010 Homework 7 Solutions 1. Problem 6.7 (just redo part a of 6.2) Here are the x and s charts from Minitab.
Xba r SCha r t of Ex 6 2 V
15. 0 12. 5 10. 0 7. 5 5. 0 LC L= 5. 92 1 3 5 7 9 11 Sa m p l e 13 15 17 19 _ _ X= 10. 32 U C L=
Statistics 664 Autumn 2010 Homework 5 Solutions 6.2 (b) From part (a) (previous homework) we saw that x = 10.32 so that the mean of all the actual voltages is 350 + 10.32/10 = 350 + 1.032 = 351.032 and we would estimate the process mean to be = 351.032. W
Statistics 664 Autumn 2010 Homework 4 Solutions 6.2 (a) From Minitab we get the following charts.
Xba r a ndRCha r t
15. 0 12. 5 10. 0 7. 5 5. 0 LC L= 5. 77 1 3 5 7 9 11 Sa m p l e 13 15 17 19 _ _ X= 10. 32 U C L= 14. 88
Sa m p l e M e a n
16 12 8 4 0 1 3
Statistics 664 Autumn 2010 Homework 3 Solutions In all of 5.17, 5.18, and 5.19 we are looking for patterns that we would think would be very unlikely if the data were random. In particular, we apply the rules discussed in class. Note that rules involving
Statistics 664 Autumn 2010 Homework 2 Solutions 3.12 Here is a normal plot from Minitab
Pr oba bi l i t y Pl ot of Y i e l d
Nor mal 95%CI
99.9 99 95 90 80 70 60 50 40 30 20 10 5 1 0.1 Mean StDev N AD P Valu e 89.48 4.158 90 0.956 0.015
Pe r ce nt
75
80
8
Statistics 664 Homework 1 Solutions 3.7 Here is the histogram from Minitab
Hi st ogr a mof Y i e l d
9 8 7 Fr e que ncy 6 5 4 3 2 1 0 84 86 88 90 Yie ld 92 94 96 98
Here is the histogram JMP
A histogram from either package is acceptable.
3.17 Time series
STATISTICS 664 Autumn 2010 Homework 8 (due Thursday Dec. 2). 1. Problem 7.2 in your text. 2. Problem 7.4 in your text. 3. Problem 7.6 in your text. 4. Problem 7.10 in your text. 5. Problem 7.14 in your text. 6. Problem 7.16 in your text.
STATISTICS 664 Autumn 2010 Homework 7 (due Tuesday Nov. 23). 1. Problem 6.7 in your text (just redo part a of 6.2). 2. Problem 6.8 in your text (just redo part a of 6.3). 3. Problem 6.42 in your text. 4. Problem 6.55 in your text. 5. Problem 6.56 in your