BF 722 Chapter 14 Problems
8. Use the DuPont system and the following data to find return on equity.
Leverage ratio
2.2
Total asset turnover
2.0
Net profit margin
5.5%
Dividend payout ratio 31.8%
CFA #5. The financial statements for Chicago Refrigerator I
Chapter 14 - Financial Statement Analysis
CHAPTER 14
FINANCIAL STATEMENT ANALYSIS
1. N
a. Inventory turnover ratio in 2009.
= 2850 / (490 + 480) x .5 = 1.47
b. Debt equity ratio in 2009.
= 3340 / 960 = 3.48
c. Cash flow from operating activities in 2009.
BF 722 Chapter 15 Problems
4. Turn back to Figure 15.1 which lists the prices of various IBM options. Use the data
in the figure to calculate the payoff and the profits for investments in each of the
following July expiration options assuming that the sto
Summary Lecture 5
This lecture focused on projectile motion. See
the summary of Lecture 4 for details. Relative
Velocity was not explicity covered this quarter
its a simple example of vector addition.
Relative Velocity
What is the relative velocity
is th
Summary Lecture 1
Kinematics: Objects in Motion
Distance traveled
Average Speed = -Elapsed Time
vs = d/t
Units: Speed is measured in [m/s]
Unit conversion:
1 mi = 1610 m
1 hr = 3600 s
1610 m
mi
1 mi
55 mph = 55
hr 3600 s
1 hr
= 24 . 6 m / s
Instantaneous
PHYSICS 111
LECTURERS
Prof. K. Honscheid
Prof. F. Yang
Prof. J. Beacom
SYLLABUS/ASSIGNMENT SHEET
Section
8:30 & 9:30
10:30 & 11:30
12:30 & 1:30
Office
PRB 3054
PRB 2006
PRB M2004
Phone
292-3287
688-4390
247-8102
SPRING 2010
e-mail
[email protected]
yang
Chapter 17 Problems
1. On January 1, you sold one March maturity S&P 500 Index futures contract at a
futures price of 800. If the futures price is 850 on February 1, what is your profit?
The contract multiplier is 250.
3.
A one-year gold futures contract
Chapter 18 - Portfolio Performance Evaluation
CHAPTER 18
PORTFOLIO PERFORMANCE EVALUATION
1. a. Possibly. Alpha alone does not determine which portfolio has a larger Sharpe ratio.
Sharpe measure is the primary factor, since it tells us the real return per
Chapter 17 - Futures Markets and Risk Management
CHAPTER 17
FUTURES MARKETS AND RISK MANAGEMENT
1. Selling a contract is a short position. If the price rises, you lose money.
Loss = (850 800) x 250 = $12,500
2. Futures price = 800 x (1 + .01 - .02) = 792
Chapter 15 - Options Markets
CHAPTER 15
OPTIONS MARKETS
1.
Options provide numerous opportunities to modify the risk profile of a portfolio. The
simplest example of an option strategy that increases risk is investing in an all options
portfolio of at the
Chapter 13 - Equity Valuation
CHAPTER 13
EQUITY VALUATION
1. Theoretically, dividend discount models can be used to value the stock of rapidly
growing companies that do not currently pay dividends; in this scenario, we would be
valuing expected dividends
BF 722 Study Guide Final Exam
Ratio Analysis
DuPont System
Compound leverage
Options profit/payoff diagrams, option strategies
In the money/at the money/out of the money options
Buyers vs. writers of options
Warrants/convertible bonds
Futures types of con
BF 722 Chapter 18 Problems
5. Based on current dividend yields and expected capital gains, the expected rates of
return on portfolios A and B are 11% and 14% respectively. The beta of A is .8 while that
of B is 1.5. The T-bill rate is currently 6%, while
BF 722 Chapter 13 Problems
10. A common stock pays an annual dividend per share of $2.10 The risk-free rate is 7%
and the risk premium for this stock is 4%. If the annual dividend is expected to remain at
$2.10, what is the value of the stock?
11. The ris
Summary Lecture 2
Acceleration
a=
v vo
t
Acceleration is change in velocity over change in
time
Uniformly Accelerated Motion
a = constant
vo = velocity at t = 0
xo = position at t = 0
x = x0 + v0 t + a/2 t2
v = v0 + a t
v = (v + v0 )/ 2
v2 = v02 + 2a (x -
Summary Lecture 3
Uniformly Accelerated Motion
a = constant
Conventions
vo = velocity at t = 0
xo = position at t = 0
Equations
x = x0 + v0 t + a/2 t2
v = v0 + a t
v = (v + v0 )/ 2
v2 = v02 + 2a (x - x0)
Falling Bodies
In the absence of air resistance all
Homework 11 Physics 181, Spring Term 2017
Posted: 04-14-2017
Due: 04-22-2017 at 7PM, submitted as a single pdf.
Please do write legibly as much as you possibly can. The TAs will be grateful for a clear
presentation of your work! Also, show your work in de
Midterm Review 1
Nicholas Mazzucca
The Ohio State University
February 17, 2016
Disclaimer: I have 0 idea whats actually going to be on the midterm. This review sheet is only
presented as a review of the material covered in recitation, up to the first midt
Summary Lecture 14
Definition of Impulse
J = F t
Useful in collisions with a time-varying force.
F is the average force during the collision,
t is the duration of the collision.
Definition of Linear Momentum
Li
p = mv
mv
The momentum p is a vector in the
Summary Lecture 13
(in an isolated system)
ENERGY IS CONSERVED
Energy <=> Work
PE = mgh
W = Fscos
KE = m/2 v2
PEE= k/2 x2
Total work on an object
W(total) = Fnet s cos
Work Energy Theorem
= KE
W(total)
WNC + WC = KE
WNC = KE + PE = Ef-Ei
If WNC = 0
E f =
Summary Lecture 12
Energy
Work
Force
Energy is the capability to do Work or
To do some work you need to transform
some energy.
Definition of Work
Work = Force x Displacement
(Force component along path!)
WF = F s cos
cos
Total work on object
W = FNet s co
Summary Lecture 11
Summary Lecture 11
Density = Mass/Volume
= m/V
Pressure = Force/Area
P = F/A
Hydrostatic Pressure in a Liquid
Pressure in Liquid
P s = hg
Total Pressure in a Liquid
P = P external + hg
Summary Lectures 10
Uniform Circular Motion
Objects moving in a circle of radius r with constant
speed
speed v
Time for 1 turn (Period): T
Speed v = 2r/T
velocity : constant magnitude
direction perpendicular to radius
= tangential to circle
Centripetal Ac
Summary Lecture 9
Newtons Law of Gravity
Newtons Law of Gravity
Force of Gravity
Directed along the line connecting the 2
masses. Always attractive.
Always attractive
m1m2
FG = G
r2
Universal Gravitational Constant
G = 6.67 x 10-11 Nm2/kg2
Apparent Weight
Summary Lecture
Summary Lecture 8
Static Friction:
Up to a maximum the static friction force is
to maximum the static friction force is
equal to the applied force. The maximum
static friction force is:
FFr(max) = s FN
Kinetic Friction:
The kinetic frictio
Summary Lecture 7
Netwons 2nd Law:
The acceleration of a body is directly
proportional to the net force acting on
it, and inversely proportional to its
mass.
Fnet = ma
The direction of the acceleration is in
the direction of the applied net force.
directi
Summary Lecture 6
Dynamics
Newtons 1st Law:
If the net force on an object is zero, an
the net force
an object is zero an
object originally at rest remains at
rest, and an object in motion remains
in motion in a straight line with const.
motion in straight
Summary Lecture
Summary Lecture 4
Adding Vectors:
Relative Velocity
e.g. a helicopter flying due west with wind
blowing from the south.
th
40 km/h
125 km/h
Magnitude of resultant velocity:
resultant velocity:
vHeli-Ground2 = vHeli-Air.2 + vAir-Ground2
Dir