Math 148 Test 1 Version A Solutions Autumn 2002
Name:
Instructor and class time:
This is the solutions to version A of the rst midterms.
h
1. (10 pts) Solve A = (b + c) for b
2
2A
c = b. Note: other versions had problems similar this one: Solve for d if
Notes for Math 148, Wed., Oct. 2
Homework questions:
1:002:05 p.m. class: A question was asked about #53 in section 1.1. The problem is easy because the
square has sides parallel to the coordinate axes. How do we solve the problem if the square is tilted?
Math 148 Quiz 1a Autumn 2002
Name:
Class time (circle one):
1:00 p.m.
2:30 p.m.
Please read all the questions carefully and show your work. Credit may not be awarded if answers are not
supported by work.
1. You have already invested $5,200 in a stock with
Math 148 Quiz 2a Solutions Autumn 2002
1. Let f (x) = 2x + 1. Find f (3 + 1).
Answer: f (3 + 1) = f (4) = 9.
2. A parabola has vertex at the point (5, 6) and a zeros at x = 7 and x = 3. Find the equation of the
parabola. (Hint: use the form y = C (x z1 )(
Solutions to problems from old Math 148 Final Exams
1. x = 4/3
2. a) f (2) = 8, f (x) = x4 x3 7x2 + 12
b) z = 2, 3
3. $236.20
4. Dimensions of sheet are 20 by 15 feet (dimensions of the box itself are: depth 2, width 11, length 16
feet).
5. a) 10 13 yards
Problems from old Math 148 Final Exams
These problems can be downloaded from the course home page:
http:/www.math.ohio-state.edu/courses/math148/
1. Solve x2 3x + 4 = x
2. Let f (z ) = z 4 + z 3 7z 2 + 12 and g (z ) = z 3 .
a. Find f (2) and f (x).
b. Fin