EE323 Homework 3- Solution, Au/2004 3.54 (25points) (a) (10points) To find the small-signal response, open the dc current source I and short the capacitors C1 and C2 . Also, replace the diode with its small signal resistance: nV rd = T . Rs and the diode
EE323 Homework 2- Solution, Au/2004 3.2 (20points) (a) Diode is conducting, and thus has a 0V drop across it. Consequently: 3 (3) = 0.6mA V = 3V , I = K 10 (b) Diode is cut off, so: V = 3V , I = 0 A (c) Diode is conducting, and thus has a 0V drop across i
EE323 Homework 1- Solution, Au/2004 2.8 (25 points) (a) Voltage gain:
Vo 100 R = 2 = = 10V / V 10 Vi R1
(b)
Input impedance: Rin = 10 K The 10Kohm resistor has not impact on the voltage gain and input impedance. V 100 R Voltage gain: o = 2 = = 10V / V 10
Due 11/29/2004, Mon EE323 Homework 8- Solution, Au/2004
1
10.25 (20 points) For PDN, Y = A + B(C + D) , which can be drawn directly; and then the PUN as direct dual. So the complete CMOS circuit is:
VDD
VDD
C
D
A
Y
A
B
C
D
10.27 (40 points)
PUN: Y = AB +
ECE323 Final Exam
(Open book)
Name (print): _
Use space provided. Show your work. Answer all 4 problems. Circle your final results.
Q1 Q2 Q3 Q4 Total
/24 /26 /25 /25 /100
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Signature: _
03/08/2006
1 Q1. (24 points) (A