Some solutions for Chapter 2 Probability 2-71. One out of 200 calls is misdirected Probability that a random call misdirected is 1/200 = 0.005 Or probability that a single call NOT misdirected is 199/200 = 0.995. Five calls are taken independently, denote
Project 3
1. A bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 175 and a standard deviation of 15. If an applicant is randomly selected, find the probability of a rating that is between 150 and 200.
2.
PROBABILITY
2-12. a) P(exploring the products) = 1790 / 2385 = 0.7505 b) P(purchase) = 387 / 2385 = 0.1623 c) P(purchase | explored the products) = 387 / 1790 = 0.2162 d) (a) approximately 75 percent of the visitors go beyond the homepage. Based on murder
INTRODUCTION AND DESCRIPTIVE STATISTICS
1-14. First, order the data: -1.2, 3.9, 8.3, 9, 9.5, 10, 11, 11.6, 12.5, 13, 14.8, 15.5, 16.2, 16.7, 18 The median, or 50th percentile, is the point in position 16(50/100) = 8. The point is 11.6. First quartile is i
Chapter 08 - The Comparison of Two Populations
THE COMPARISON OF TWO POPULATIONS
8.2 H0: D = 0 H1: D 0; n = 40 D =5 s D = 2.3
CHAPTER 8
4 5
tt = 13.75. Strongly reject H0. 95% C.I. for D 2.023(2.3/ 40 ) = [4.26, 5.74]. n = 60 D = 0.2 s D = 1; H0: D 0 H1:
HYPOTHESIS TESTING
7.16 7-18 H0: = 31.5 ; H1: 31.5 n = 100 x = 29.8 s = 6.6; z = -2.575 . The p-value is approximately 0.01 Reject H0 at = 0.05 (and almost at = .01). H0: = 5 H1: 5 = .05 n = 120 x = 2.3 s = 1.5; z = -19.72 Reject H0 at = .05 and at smalle
Business Statistics Assoc. Prof. Ho Thanh Phong School of Business, International University Term Project Objectives To apply concepts and techniques in Statistics into some real world problems. To show capability in team working for problem solving. To p
A
q
Statistical Tables
Cumulative Binomial Distribution q Area of Standard Normal Distribution q Critical Values of t Distribution q Critical Values of Chi Square Distribution q Critical Values of the F Distribution
ATA ANALYSIS TECHNIQUES
A-2
Cumulative