Exam One Solutions
Problem 1
Western University has only one womens softball scholarship remaining for the upcoming year.
The final two players that Western is considering are Allison Fealey and Emily Janson. The
coaching staff has concluded that the spee

Yiyuan Cao
bus 109
number 7
percent frequency distribution
rating
frequencypercent frequency
excellent
20
40
very good
23
46
good
4
8
fair
1
2
poor
2
4
total
50
100
25
20
15
Column B
10
5
0
excellent
very good
good
fair
poor
most of people satisfied the D

Angela (Yueyi) Qin
Professor Winnington
Business 109
29 April 2015
Asia Matters for America / America Matters for Asia
On Wednesday, February 18 at 5pm in the Hynson Lounge, I attended the panel
discussion on "Why Asia Matters." Four Doctors on Asia gave

Chapter 4
The probability of at least one head in two flips of a coin is
a. 0.33
b. 0.50
*c. 0.75
d. 1.00
The complement of P(A | B) is
a. P(AC | B)
b. P(A | BC)
*c. P(B | A)
d. P(A B)
The probability of an intersection of two events is computed using the

Managerial Statistics (BUS 109)
Exam Three Solutions
Your Name (please print): _
1. A production line operation is designed to fill cartons with laundry detergent to a mean
weight of 32 ounces. A sample of cartons is selected each hour and weighed to dete

Week Two Homework Assignment Solutions
Problem 5
a.
x
xi 3181
$159
n
20
b. Median
10th $160 for Los Angeles
11th $162 for Seattle
Median =
160 162
$161
2
c. Mode = $167 ; San Francisco and New Orleans
d. i
20 5
100
25
5th $134
6th $139
Q1
134 139

Week Three Homework Assignment Solutions
Problem 11
a. Total motorcyclists = 350 + 170 = 520
P(DOT-Compliant Helmet) =
350
.6731
520
b. Yes, the overall probability has been increasing from .48 five years ago, to .63 one
year ago, and is now approximatel

Week Six Homework Assignment Solutions
Problem 11
a.
x xi / n
b. s
$45,500
$4,550
10
( xi x ) 2
n 1
9, 068, 620
$1003.80
10 1
Problem 21
x / n 100 / 90 10.54 This value for the standard error can be used for parts (a)
and (b) below.
a.
z
512 502
.95

Week Eleven Homework Assignment Solutions
Problem 19
a. H0: 12
Ha: < 12
x 0 1012
1.77
n 8 50
b.
z
c.
p-value is the area in the lower tail
Using normal table with z = -1.77: p-value = .0384
Using Excel: p-value = NORM.S.DIST(-1.77,TRUE) = .0384
d.
p-valu

Week One Homework Assignment Solutions
Problem 5
a.
.Name
Frequency
Brown
7
.14
14%
Davis
6
.12
12%
Johnson
10
.20
20%
Jones
7
.14
14%
Smith
12
.24
24%
Williams
8
.16
16%
50
1.00
Relative
Frequency
Percent
Frequency
b.
Frequency
14
12
10
8
6
4
2
0
Brown
c

Exam Two Solutions
Problem 1
= 328 and = 92
a.
z
x
500 328
1.87
92
P(x > 500) = P(z > 1.87) = 1 - P(z 1.87) = 1 - .9693 = .0307
The probability that the emergency room visit will cost more than $500 is .0307.
b. z x 250 328 .85
92
P(x < 250) = P(z < -.8

Week Seven Homework Assignment Solutions
Problem 17
For the Miami data set, the output obtained using Excels Descriptive Statistics tool
follows:
Rating
Mean
6.34
Standard Error
0.3059
Median
6.5
Mode
8
Standard Deviation
2.1629
Sample Variance
4.6780
Kur

Last Name
Brown
Smith
Davis
Johnson
Williams
Williams
Johnson
Jones
Davis
Jones
Williams
Jones
Smith
Smith
Davis
Johnson
Smith
Jones
Jones
Johnson
Williams
Smith
Brown
Smith
Johnson
Jones
Smith
Smith
Williams
Brown
Williams
Johnson
Williams
Johnson
Willia