Chris Andersen
Randomness
HW10
1)
a. x*y does not produce an eigenvector because an (n x 1) matrix (x) multiplied
by a (1 x n) matrix (y) produces an (n x n ) matrix, and in order to be a right
eigenvector it must be an (n x 1) matrix.
b. A * x = (n x n)
1a) It is given that the variance of X and Y are 1 and because they are independent their
covariance is 0.
2c) see problem2c.m
3c) see getData.m
3d) see problem3d.m
Chris Andersen
Problem set 8
1.
a. Through induction we are able to conclude that the PMF and the expected value
are both 0.5. If you put in different values of p you will always get 0.5.
The variance is 0.25
Chris Andersen
Problem set 8
b. Seen in figure
Christopher Andersen
Problemset 7
Christopher Andersen
Problemset 7
2)
a. 2x-y has values 1, 2, 4, .5, .25, .125 when plugging in
values for x = cfw_1,2,3 and y = cfw_1,2,3,4
P(1) = .1900
P(X=1,y=1) = .1500 + P(X=2,y=2) = .0000 + P(X=3,y=3) = .
0400
P(2)
Christopher Andersen
Randomness
PS5
1)
a.
Christopher Andersen
Randomness
PS5
b.
2)
a. see problem2a.m
Christopher Andersen
Randomness
PS5
b. see problem2b.m
3)
a. solve (P(H | p)*P(p)/(P(H)
you can reduce P(H | p) to p. when you know p that becomes the p
Christopher Andersen
Randomness
HW4
1)
a.
b.
figure 1b shows the histogram plot of the data. You see that 2 appears most often opposed
to all the values having an equal probability.
2)
Christopher Andersen
Randomness
HW4
3)
4)
a. see problem4a.m
b. P(n) =
Chris Andersen
Randomness
PS3
1)
a. S= 26^6
E = 6chose2(25^4)
P(E)= E/S
b. S=63^5
E= 53*63*63*1*1
P(E) = E/S
Chris Andersen
Randomness
PS3
c. S=8!
E = 8*2*6!
P(E) = E/S
Chris Andersen
Randomness
PS3
2)
Chris Andersen
Randomness
PS3
a.
Chris Andersen
Rando
Christopher Andersen
Problem Set 2
Randomness
1)
a. In problem1a.m the script goes through 10^6 randomly generated 6-letter
words. The probability after 10^6 tries of getting the word path was around
3.0000e-06. Path was not found in anything less than 10
Christopher Andersen
Problem set one
1
a) given
b) x=1-(y=z)
y=z gives you a comparison of each element of the matrix as opposed to the
entire thing like y=z would give.
2
a) check folder for tetraRoll.m
b) hist.fig in the folder shows that the results do