ENGINEERING PROFESSIONAL EDUCATION - EXAM COVER SHEET
EXAM INFO
Exam Number: Final
Scheduled Exam Date: May 1, 2013
PROFESSOR (THE FOLLOWING MUST BE COMPLETED BY THE PROFESSOR.)
COURSE: ME 559
PROFESS
Page 1
Problem 1. Consider the 45-degree off-axis tensile coupon. If the material properties
are:
E1 = 140 GPa, E2 = 10 GPa, 612 = 7 GPa and v12 = 0.3
The stiffness matrix for the 45-degree off-axis s
. . . l l DI!
3.73 33:! 3332 VI JV JI pill. U V «(U D
PROBLEM #1 (50 points)
in composite mechanics one important concern is that of localization. That is
' given an applied strain state one aims to
Q2 ]
Now using the rule of mixture. We can assumes that the modulus of a composite is the
combination of the modulus of the fiber and the matrix that are related by the volume fraction
of the constitu
Part #1 (40pts):
1
Pm EE=I+§fa(BT) CM
oar1
Part #2 (60pts):
For a short ber reinforced composite made of an aluminum matrix (A1) with SiC Fibers (25%)
compute the stiffness and compliance matrices usi
ME559 Micromechanics of Materials, Spring 2013
Homework #4
Assigned 3/6/2013
Due 3/20/2013
Part #1 (40pts):
Proof
cfw_
N
(
C = I + f B T
=1
)
1
CM
Part #2 (60pts):
For a short fiber reinforced co
ME559-HW2-Spring 2011.
Leye Amoo
1. Matrix: E = 50,000 MPa, Fracture Stress for the matrix is 200 Mpa
Fiber: E= 350 000 Mpa, Fracture stress for the fiber is 1000 Mpa
(a) We want failure stress of the
FE Modeling of Composite
Materials
ME 559 Micromechanics of
Materials
ME559
Thomas Siegmund/Purdue
FE-Model?
http:/www.scielo.br/img/fbpe/jbsms/v23n1/a01fig2c.gif
ME559
Thomas Siegmund/Purdue
Motivati
Property Predictions
ME 559 Micromechanics of Materials
ME 559
T. Siegmund ME/Purdue
1/Chapter 4
Goals
Employ results obtained from eigenstrain/eigenstress
analysis to homogenization
Special case: s
Basic Composite Mechanics:
Why Composites?
ME 559 Micromechanics of
Materials
ME 559
T. Siegmund ME/Purdue
1/Chapter 1
The Material Space is Empty
1000
Modulus [GPa]
Beryllium
Alumina
100
Aluminum
10
Basic Composite Mechanics:
Why Composites?
ME 559 Micromechanics of
Materials
ME 559
T. Siegmund ME/Purdue
1/Chapter 1
The Material Space is Empty
1000
Modulus [GPa]
Beryllium
Alumina
100
Aluminum
10
1
Determination of the value of distributed load applied on a glass
plate according the damage equivalent stress concept
- The plate is made from glass. It has rectangular shape with dimensions
2a=1m;
PROBLEM #1
Starting from a honeycomb and setting h=0 and 0=4S°
squarenshaped cells in which the cell walls are diagonal
remaining cell wall length is L, the wall thickness
one arrives at a cellular st
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Abstract
Stiffness Healing Efficiency in Self Healing Hockey Sticks
Student Name
Purdue University, ME559
The stiffness healing efficiency for a hollow fiber self-healing composite is demonstrated as
Composite Mechanics of the Yucca Leaf
Your Name
ME559 Spring 2017
Purdue University
The leaf of the yucca plant has long been used as a biological substance to extract fibrous
materials to create rope