ChE 20500 Hour Exam 2: Fall 2013, October 24, 2013 (8:00p 9:30p)
Instructions: Please complete the following problems on separate, numbered pages. Start each problem on a new page
and write only on one side of a piece of paper. Only one side of a piece of
Question 1
Part a:
Part b:
Using RH
y0 805 mmHg = 0.421 P (37C ) +3
from table B.3
P (37C ) = 47.067mmHg +3
y0 = 0.421 P (37C )
0.421 47.067mmHg
= 0.025
805mmHg
+2
Part c:
7C = 280.15K
using ideal gas EOS
P V = n1 R T +2
n1total
P V
=
= 22.9mol / h +1
R T
ChE 20500 Hour Exam 2: Spring 2015, April 1, 2015 (8:00p 9:30p)
Problem 1. (35 points total)
A large refrigeration laboratory houses biological samples at colder temperatures in order to prevent degradation of the
samples. Researchers work inside of this
ChE 20500 Hour Exam 1: Spring 2014, February 17, 2015 (8:00p 9:30p)
Problem 1. (45 points total)
Sugar is manufactured through the refinement of plants called sugar cane. In this process, sugar cane is fed into a milling
unit to be refined. The sugar cane
Purdue University ChE 205: Chemical Engineering Calculations, Spring 2017
A. Instructors. Professor Beaudoin and Professor Morgan
B. Catalog Description. Quantitative applications of steady-state mass and energy balances to solve problems
involving multi-
CHE 201 Tutorial #7
Q1
The reaction between ethylene and hydrogen bromide to form ethyl bromide is carried out in a continuous
reactor. The product stream is analyzed and is found to contain 50 mol% C 2H5Br and 33.3% HBr. The feed to
the reactor contains
ChE 20500 Hour Exam 2: Spring 2014, April 3, 2014 (8:00p 9:30p)
Problem 1 (40 points total). An air conditioning unit acquires air from outside of the building at a certain volumetric flow rate in
order to provide a comfortable environment to the occupant
ChE 20500 Hour Exam 1: Fall 2016, September 28, 2016 (8:00p 9:30p)
Instructions: Please complete the following problems on separate, numbered pages. Start each problem on a new page and write
only on one side of a piece of paper. Only one side of a piece
ChE 20500 Hour Exam 3: Fall 2011, November 21, 2011 (8:00 9:30p)
Instructions: Please complete the following problems on separate, numbered pages. Start each problem on a new page
and write only on one side of a piece of paper. Only one side of a piece of
ChE 20500 Hour Exam 2: Fall 2016, October 26, 2016 (8:00p 9:30p)
Instructions: Please complete the following problems on separate, numbered pages. Start each problem on a new page and
write only on one side of a piece of paper. Only one side of a piece of
ChE 20500 Hour Exam 3: Fall 2015, December 1, 2015 (8:00p 9:30p)
Instructions: Please complete the following problems on separate, numbered pages. Start each problem on a new page
and write only on one side of a piece of paper. Only one side of a piece of
ChE 20500 Exam 1 Fall 2015
Problem 1
B = benzene, C6H6
T = toluene, C7H8
X = xylene, C8H10
Points for part a (5 pts total):
1 pt each for correct mix point, DC #1, DC #2, split point (4 pts)
1 pt for correct symbology (y for vapor, x for liquid, for flow)
February 3, 2017
Lecture 11: Gas Laws
Learning objectives
1. Apply non-ideal gas equations to real systems
2. Distinguish ideal and non-ideal conditions
Describe non-ideal (Real) gases
describing change from ideal state
Ideal gas
=1
or
=
Virial Equation
CHE211Fall2012
Exam#1
09/21/2012
ookandNotes)
1.
(30 Points).
Write down in words only (no equations and no symbols) the description of the
equationsofenergybalancefor(a)(10Points)aclosedsystem
and(b)(20Points)anopensystemincludeasketch.Inthiscase,ignore
ChE 20500 : Chemical Engineering Calculations:
Hour Exam 2
Summer 2016
Time Allowed:
90 minutes
Total Points:
100 points
SHOW ALL WORKING ON THE EXAM PAPER. Numerically correct answers with
insufficient justification may not receive full credit.
STUDENT N
ChE 20500 : Chemical Engineering Calculat ons:
Hour Exam 3
Summer 2016
Time Allowed:
90 minutes
Total Points:
100 points
SHOW ALL WORKING ON THE EXAM PAPER. Numerically correct answers with
insufficient justification may not receive full credit.
STUDENT N
1
1
1.1
Practice Exam B
Polarizers
A clear sheet of polaroid is placed on top of a similar sheet so that their polarizing
axes make an angle of 60 degrees with each other. The ratio of the intensity of
emerging light to the incident unpolarized light is:
MMLQQigtijnigtaj); A liquid water stream contains 12% (by wt.) pyridine, a valuable product. WC dCSITC 1)
remove the majority of pyridine from this stream using a process known as liquidliquid extraction. in this process, the
feed stream (water and pyridi
Problem 1
Part a
+1 for each unit
operations
+1 for proper labels
1
Part b
DOF crystallizer
2 unknowns 2 [ m 9 , m 7 ] +2
-2 balances [sugar, water (or overall)] +2
DOF = 0 +1
DOF evaporator
4 unknowns [ m 6 , m 5 , m 7 , x 5 sugar ] +2
-2 balances [sugar
ChE 20500 Hour Exam 1: Fall 2015, October 1, 2015 (8:00p 9:30p)
Instructions: Please complete the following problems on separate, numbered pages. Start each problem on a new page and
write only on one side of a piece of paper. Only one side of a piece of
ChE 20500 Hour Exam 2: Fall 2015, November 4, 2015 (8:00p 9:30p)
Instructions: Please complete the following problems on separate, numbered pages. Start each problem on a new page and
write only on one side of a piece of paper. Only one side of a piece of