CE 473
Homework - Ch. 22
Section 22 Questions
1. Draw a moment diagram for the beam shown
A
B
Given:
Nominal Moment Capacity
Span
M n := 300kip ft
L = 21ft
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CE 473
Homework - Ch. 22
Solution
The shape of the moment diagram is:
This m
CE 473
Homework - Ch. 19
3/31/2012
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Section 19 Questions
Compute the short-term deflection of beam CD
Given:
Span
Ln := 24ft 18in = 22.5 ft
Cross-sectional width
b := 12in
Cross-sectional depth
h := 22in
Moment distribution
Curvature distributi
CE 473
Homework - Ch. 18
Section 18 Questions
Compute the moment capacity of the section shown
Given:
Nominal concrete strength:
f'c := 3ksi
Estimated comp. strength of conc.:
f'c := 0.85 f'c
Ratio of average unit stress to f'c:
k1 := 0.85
Unit yield stre
CE 473
Homework - Ch. 17
3/31/2012
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Section 17 Questions
Add 5 Gr.-60 #9 bars near
the top of this section and
estimate the moment capacity
of the resulting section.
ooooo
Given:
Nominal concrete compressive strength
f'c := 4ksi
Steel unit yiel
CE 473
Homework - Ch. 13
3/25/2012
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Section 13 Questions
SECTION 1
SECTION 2
Relevant Expressions:
Moment:
1
M = fc b ( k d ) ( j d )
2
Internal Lever Arm in Linear Range:
j d = 1
Relative Depth to N.A. in Linear Range:
k = n + 2 n n
k
d
3
22
CE 473
Homework - Ch. 12
3/30/2012
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Section 12 Questions
Relevant Expressions:
Moment of interia of a rectangle (about c.g.):
1
3
Ic =
base height
12
Moment of inertia about axis parallel to
centoridal axis:
I = Area dsiatance + Ic
Moment at c
CE 473
Homework - Ch. 11
Section 11 Questions
Relevant Expressions:
Moment:
M = As fs j d
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CE 473
Homework - Ch. 11
Given:
Unit stress at yield:
fy := 60ksi
Span:
L := 24ft
Effective depth:
d := 24in
Ratio of internal arm to d:
j := 0
CE 473
Homework - Ch. 10
Section 10 Questions
Relevant Expressions:
Curvature:
Confining Unit Stress
=
=
x
s
dc
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Homework - Ch. 10
3/20/2012
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Given:
Change in Slope
:= 4deg = 0.07 rad
Length
x := 18ft
Effective dept
CE 473
Homework - Ch. 8
2/6/2012
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Section 8 Questions
Relevant Expressions:
Volumetric Ratio of Spiral Reinforcement:
2 Ash
h = 2
d c s
Confining Unit Stress
1
f2 = h fyh
2
Strength of Confined Concrete
f1 = f'c + 4.1 f2
Given:
Concrete Cylind
CE 473
Homework - Ch. 7
2/5/2012
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Section 7 Questions
1)
Determine the limiting load to be used in design for the column section described in Example 1.
Assume #9 bars are to be used as longitudinal reinforcement.
Relevant Expressions:
1
Pdesig
Homework - Ch. 5
CE 473
Section 5 Questions
QUESTION 1
The total weight of the buidling and its contents is
3
Wtotal := 10 40ft 40ft ( 200psf + 30psf ) = 3.7 10 kip
The total weight carried by th einterior column in the first story is
P := Wtotal 4 = 920