Solution for Hw#1
2-2 The viscosity of a liquid detergent is supposed to average 800 centistokes at 25C.
A random sample of 16 batches of detergent is collected, and the average viscosity is 812.
Supp
STAT 514 Homework 1
Due Jan 20
Optional: Reading assignment: IntroSAS.doc in the blackboard learning or equivalent online material if not
familiar with SAS programming.
1. Randomization Test: In a stu
Assignment 3
(On-campus students: due 5pm, 09/27/2011; O-campus students: due
midnight, 09/29/2011 )
1. To study the eect of pesticide on birds, a scientist randomly and equally allocates N = 65
chick
Assignment 3 Answer Keys
1. In the experiment, a = 5 and n1 = n2 = . . . = na = 13. Only the summary statistics,
sample means (i. ) and sample standard deviatiuons (si ), are given. Although the origi
Stat514F10 Midterm II (Total 20 Points)
0. Exam time: 2 hours; 1. Use = 5% throughout the exam; 2. Must show work to
get credits 3. Hand in both the question and answer sheets.
1. An experiment is con
Assignment 2
(On-campus students: due 3pm Friday 09/16/2011; o-campus students: due
midnight Saturday 09/17/2011)
1.
An article in the Journal of Strain Analysis (vol. 18, no.2 , 1983) compares severa
Midterm 1 Solution Problem 1 a) The factor is the safety program of two levels: with or without it; b) Though all the three principles randomization, replication and blocking were followed in the expe
Assignment 3 Answer Keys
1. In the experiment, a = 5 and n1 = n2 = . . . = na = 13. Only the summary statistics, sample means (i. ) and sample standard deviatiuons (si ), are given. Though the origina
Assignment 10 (do not need to hand in)
1. An engineer is interested in the eects of cutting speed (A), tool geometry (B ), and
cutting angle (C ) on the life (in hours) of a machine tool. Tow levels o
Assignment 2 Answer Keys
1. Because the two samples are paired, the paired t-test based on the dierences of the two
samples should be used. The dierences are
d1
d2
d3
d4
d5
d6
d7
d8
d9
0.125 0.159 0.2
Assignment 1 (Due 5pm Thursday, 09/08/11)
1.
In an experiment, two types of fertilizer mixtures A and B are used to treat six bean plants,
with each randomly applied to three of the plants. The yields
Assignment 2
Due Thursday (09/15/05) 1. An article in the Journal of Strain Analysis (vol. 18, no.2 , 1983) compares several procedures for predicting the shear strength for steel plate girders. Data
STAT 514 Design of Experiments
Problem 1
(a) The hypotheses are H0 : vs H1 :
Homework 8
There is no difference between the four assembly methods, or symbolically, A = B = C = D . There is a difference
Stat514F2010 Final Exam (Total 40 Points)
1. Exam time: two hours and ten minutes 2. Use = 5% throughout the exam. 3.
Must show work to get credits. 4. Hand in both question and answer sheets.
1. To s
Latin Square Design
Block on two nuisance factors
One trt observation per block1
One trt observation per block2
Must have same number of blocks and treatments
Latin Square Design
Two restrictions
Factorial Experiments with
Random Eects
Topics 14-16 have focused on xed eects
Always use MSE in denominator of F-test
Use MSE in linear combinations and CIs
Random and Mixed Factorial
Not always
Analysis of Variance
Interested in comparing
Several treatments
Several levels of one treatment
Comparison of a Population
Could do numerous two-sample t-tests but .
ANOVA provides method of join
Assignment 4
(Due next Friday 09/30/05) 1. A factor with three levels was studied in an experiment. The data is given as follows, in which the first column includes the treatments and the second colum
Assignment 1 Answer Keys
1.
H0 : B = A vs H1 : B = A
6
3 = 20 ways to allocate 3As and 3B s to the six plants. The 20 possible
average dierences between B and A are
a) There are
2.67, 2, 1.33, 1.33, 1
Assignment 1 (Due Thursday, 09/08/05)
1.
Two types of fertilizer mixture A and B are used to feed six bean plants with each randomly
applied to three plants. The yields of the plants (in pounds) are g
Denitions
Factors A and B are considered crossed if
Every level of B occurs with every level of A
A factorial model involves crossed factors
Factor B
1
2
3
Nested Factors
A
B
1
2
x
x
1
x
x
Design of
Homework 5 Solution
Problem 1
(a) Let's look at the ANOVA table output from SAS.
Sum of Squares 6026.83333 5767.00000 11793.83333
Source Model Error Corrected Total
DF 3 20 23
Mean Square 2008.94444 2
Assignment 5
(Due next Friday (10/28/05) 1. A chemist wishes to test the effects of four chemical agents on the strength of a particular type of cloth. Because there might be variability from one bolt
STAT 514 Design of Experiments
Homework 4 Solution
Problem 1
(a) SAS generates the following ANOVA table.
Source
DF
Sum of
Squares
Mean Square
F Value
Pr > F
Model
3
6026.83333
2008.94444
6.97
0.0022
Assignment 3
Due next Thursday (09/22/05) 1. To study the effects of pesticides on birds, a scientist randomly and equally allocates N = 65 chicks to five diets (a control and four with a different pe
Stat514F05 Midterm I (Total 40 Points)
0. Exam time: one hour and 30 minutes. 1. Use = 5% throughout the exam. 2. Must show work to get credits. 3. Hand in both your exam and answer sheets. 1. An anal
Assignment 9 (Due Thursday 4/3/08)
1. An engineer is interested in the effects of cutting speed (A), tool geometry (B), and
cutting angle (C) on the life (in hours) of a machine tool. Tow levels of ea
Statistics 514: Design and Analysis of Experiments
Lecture 5: Comparing Treatment Means
Montgomery: Sections 3.3-5
Page 1
Statistics 514: Design and Analysis of Experiments
Linear Combinations of Trea
CHM 424
October 25, 2017
immunochemical analysis
Assignment 9
CHM 424
Advanced optical methods, Ion mobility, electrophoresis,
Due Nov 1, 2017 Scaled to 15 points
NOTE Use class notes and the literatu
Midterm I Solution
1.
(a) The experimental factor is lactation status with two levels.
The 10 mothers or subjects with low calcium intakes are experimental units.
(b) Randomization: The researchers r
STAT 514 Homework 5
Due: Oct 9
1. Suppose you performed an ANOVA with a = 4 treatments and n = 5 observations per
treatment. If the M SE = 16 and = 0.05, what would the minimum difference have to
be b
STAT 514 Homework 3
1. A factor with three levels was studied in an experiment. The data is given as follows,
in which the first column includes the treatments and the second column includes the
respo