ME 452 - Machine Design II
Name of Student:_
Spring Semester 2014
Lecture Division Number:_
Homework No. 1 (40 points). Due at the beginning of lecture on Friday, January 24th.
Important notes for homework assignments (applicable to all homework this seme
ME 452 - Machine Design II
Name of Student:_
Spring Semester 2014
Lecture Division Number:_
Homework No. 1 (50 points). Due at the beginning of lecture on Friday, January 24th.
Important notes for homework assignments (applicable to all homework this seme
ME 452 - Machine Design II
Name of Student:_
Spring Semester 2014
Lecture Division Number:_
Project 1. Due at the beginning of lecture on Monday, February 3rd.
A formal report is not required for this project. The solution must be presented on engineering
ME 452: Machine Design II
Solution to Homework Set 4.
Moment arm should be 142 mm not 138 in this solution
Problem 1. (Problem 6-29, page 351)
The figure is a drawing of a 4- by 20-mm latch spring. A preload is obtained during the
assembly by shimming und
Chapter 1
Problems 1-1 through 1-6 are for student research. No standard solutions are provided.
From Fig. 1-2, cost of grinding to 0.0005 in is 270%. Cost of turning to 0.003 in is
60%.
Relative cost of grinding vs. turning = 270/60 = 4.5 times
Ans.
_
1-
Chapter 17
17-1
Given: F-1 Polyamide, b = 6 in, d = 2 in with n = 1750 rev/min, H nom = 2 hp, C = 9(12) =
108 in, velocity ratio = 0.5, K s = 1.25, n d = 1
V = d n / 12 = (2)(1750) / 12 = 916.3 ft/min
Eq. (17-1):
D = d / vel ratio = 2 / 0.5 = 4 in
42
Dd
ME 452 - Machine Design II
Name of Student:_
Spring Semester 2016
Lecture Division Number:_
Project 3. Due at the beginning of lecture on Monday, April 25th. A formal report is not required.
Design the spur gears that would be suitable for a commercial 3-
ME 452: Machine Design II
Spring Semester 2016
Instructor: Professor Gordon R. Pennock
ME 3003F (494-5728), email: [email protected]
Office Hours: M &W 11:00 am 12:00 pm
Lectures: Division 1
MWF 9:30 am 10:20 am
Room: ME 1061
Division 2
MWF 1:30 pm 2
ME 452 - Machine Design II
Name of Student:_
Spring Semester 2016
Lecture Division Number:_
Project 1. Due at the beginning of lecture on Monday, February 1st.
A formal report is not required for this project. The solution must be presented on engineering
ME 452: Machine Design II
Homework Set 13 with Solution
Problem 1.
A plate clutch has a single pair of mating friction surfaces, 300 mm outside diameter, and
225 mm inside diameter. The mean value of the coefficient of friction is 0.25, and the
actuating
Chapter 16
16-1 Given: r = 300/2 = 150 mm, a = R = 125 mm, b = 40 mm, f = 0.28, F = 2.2 kN, 1 = 0, 2 = 120, and a = 90. From which, sin a = sin90 = 1. Eq. (16-2):
Mf 0.28 pa (0.040)(0.150) 120 0 sin (0.150 0.125 cos ) d 1 2.993 10 4 pa N m
Eq. (16-3):
MN
Chapter 13
d P 17 / 8 2.125 in
N
1120
dG 2 d P
2.125 4.375 in
N3
544
13-1
NG PdG 8 4.375 35 teeth
Ans.
C 2.125 4.375 / 2 3.25 in
Ans.
_
nG 1600 15 / 60 400 rev/min
p m 3 mm Ans.
13-2
Ans.
C 3 15 60 2 112.5 mm Ans.
_
NG 16 4 64 teeth
13-3
Ans.
dG NG m 64
Chapter 14
d
14-1
N
22
3.667 in
P
6
Table 14-2:
Y = 0.331
dn (3.667)(1200)
Eq. (13-34): V
1152 ft/min
12
12
1200 1152
Eq. (14-4b): K v
1.96
1200
H
15
Eq. (13-35) : W t 33 000
33 000
429.7 lbf
V
1152
K vW t P 1.96(429.7)(6)
7633 psi 7.63 kpsi Ans.
Chapter 2
2-1
From Tables A-20, A-21, A-22, and A-24c,
(a) UNS G10200 HR: S ut = 380 (55) MPa (kpsi), S yt = 210 (30) Mpa (kpsi) Ans.
(b) SAE 1050 CD: S ut = 690 (100) MPa (kpsi), S yt = 580 (84) Mpa (kpsi) Ans.
(c) AISI 1141 Q&T at 540C (1000F): S ut = 8
Chapter 6
Eq. (2-21):
Eq. (6-8):
Table 6-2:
Eq. (6-19):
Sut 3.4 H B 3.4(300) 1020 MPa
Se 0.5Sut 0.5(1020) 510 MPa
a 1.58, b 0.085
b
ka aSut 1.58(1020) 0.085 0.877
Eq. (6-20):
6-1
kb 1.24d 0.107 1.24(10) 0.107 0.969
Se ka kb Se (0.877)(0.969)(510) 433 MPa
Chapter 4
For a torsion bar, k T = T/ = Fl/, and so = Fl/k T . For a cantilever, k l = F/ , = F/k l . For
the assembly, k = F/y, or, y = F/k = l +
Thus
F Fl 2 F
y
k
kT kl
Solving for k
kk
1
k 2
2l T
Ans.
l
1 kl l kT
kT kl
_
4-1
For a torsion bar, k T =
Chapter 9
Figure for Probs.
9-1 to 9-4
9-1
Given, b = 50 mm, d = 50 mm, h = 5 mm, allow = 140 MPa.
F = 0.707 hl allow = 0.707(5)[2(50)](140)(103) = 49.5 kN Ans.
_
9-2
Given, b = 2 in, d = 2 in, h = 5/16 in, allow = 25 kpsi.
F = 0.707 hl allow = 0.707(5/16
Chapter 7
7-1
(a) DE-Gerber, Eq. (7-10):
A 4 K f M a 3 K fsTa 4 (2.2)(70) 3 (1.8)(45) 338.4 N m
2
2
2
2
B 4 K f M m 3 K fsTm 4 (2.2)(55) 3 (1.8)(35) 265.5 N m
2
2
2
6
8(2)(338.4) 2(265.5) 210 10
d
1 1
6
6
210 10 338.4 700 10
3
d = 25.85 (10 ) m = 25.8
Chapter 11
11-1
For the deep-groove 02-series ball bearing with R = 0.90, the design life x D , in multiples
of rating life, is
L
60D nD 60 25000 350
xD D
525 Ans.
LR
L10
106
The design radial load is
FD 1.2 2.5 3.0 kN
1/3
Eq. (11-6):
525
C10 3.0
1/1.4
Chapter 8
Note to the Instructor for Probs. 8-41 to 8-44. These problems, as well as many others in this
chapter are best implemented using a spreadsheet.
8-1
(a) Thread depth= 2.5 mm Ans.
Width = 2.5 mm Ans.
d m = 25 - 1.25 - 1.25 = 22.5 mm
d r = 25 - 5
Chapter 10
10-1
From Eqs. (10-4) and (10-5)
KW K B
4C 1 0.615 4C 2
4C 4
C
4C 3
Plot 100(K W K B )/ K W vs. C for 4 C 12 obtaining
We see the maximum and minimum occur at C = 4 and 12 respectively where
Maximum = 1.36 % Ans.,
and Minimum = 0.743 % Ans.
_
Chapter 15
15-1
Given: Uncrowned, through-hardened 300 Brinell core and case, Grade 1, N C =
109 rev of pinion at R = 0.999, N P = 20 teeth, N G = 60 teeth, Q v = 6, P d = 6
teeth/in, shaft angle = 90, n p = 900 rev/min, J P = 0.249 and J G = 0.216 (Fig.
ME 452: Machine Design II
Homework Set 4 with Solution
Problem 6-56, page 353
In the figure shown, shaft A, made of AISI 1020 hot-rolled steel, is welded to a fixed
support and is subjected to loading by equal and opposite forces F, via shaft B. A
theoret
ME 452: Machine Design II
Homework Set 6 with Solution
Problem 1
An 02-series ball bearing is to be selected to carry a radial load of 8 kN and a thrust
load of 4 kN. The desired life, LD, is to be 5000 hours with the inner ring rotating at 900
rpm. Selec
ME 452: Machine Design II
Homework Set 7 with Solution
Problem 1 (Problem 13-10, page 721).
For a spur-gear set with = 20 degrees, while avoiding interference, find:
(a) The smallest pinion tooth count that will run with itself,
(b) The smallest pinion to
ME 452 - Machine Design II
Name of Student:_
Spring Semester 2017
Lecture Division Number:_
Homework No. 9 (50 points). Due at the beginning of lecture on Wednesday, April 5th.
Solve the following problems from Chapter 10, Shigleys Mechanical Engineering
ME 452 - Machine Design II
Name of Student:_
Spring Semester 2017
Lecture Division Number:_
Homework No. 7 (50 points). Due at the beginning of lecture on Friday, March 3rd.
Solve the following problems from Chapter 12, Shigleys Mechanical Engineering Des
ME 452 - Machine Design II
Name of Student:_
Spring Semester 2017
Lecture Division Number:_
Homework No. 6 (50 points). Due at the beginning of lecture on Friday, February 24th.
Solve the following problems from Chapter 11, Shigleys Mechanical Engineering