1
Chem 1080 workshop 17: Thermochemistry III
1. Some useful facts
3
(a) The energy for all monoatomic ideal gases is U = 2 nRT , where R = 8.31 J/(mol
5
K). Rigid linear molecules obey the law: U = 2 nRT . (The best example of a rigid
linear molecule is N

1
Chem 1080 workshop 16: Principles of thermochemistry II
1. Some useful facts
3
(a) The energy for all monoatomic ideal gases is U = 2 nRT , where R = 8.31 J/(mol
5
K). Rigid linear molecules obey the law: U = 2 nRT . (The best example of a rigid
linear

1
Chem 1080 workshop 15: Principles of thermochemistry I
1.1
Some useful facts
1. This problem set will focus on cylindrical pistons filled with ideal gases. A cylindrical piston is
a sealed cylinder where the upper wall of the cylinder (with area A and i

1
Chem 1080 workshop 14: Thermochemistry with some kinetics
1. The melting point of mercury is -38.87o C. Its heat of fusion is 11.80 J/g. On the average, the specic
heat of solid Hg is 0.1280 J/g; that of liquid Hg is 0.1406 J/g. If a 10 g chunk of solid

1
Chem 1080 workshop 8: The steady state approximation
1. Intermediates and catalysts
(a) A reaction intermediate is a compound, which while produced by an initial reaction
step, is consumed in a subsequent reaction step. Intermediates are present neither

Chem 1080 workshop7: AP free response kinetics questions from 2009-2011
2010 AP CHEMISTRY FREE-RESPONSE QUESTIONS
8 H +(aq) + 4 Cl (aq) + MnO4(aq) 2 Cl2(g) + Mn3+(aq) + 4 H2O(l)
3. Cl2 (g) can be generated in the laboratory by reacting potassium permangan

1
Chem 1080 workshop 6: Reaction mechanisms
1. Two reaction steps, a slow one followed by a fast one:
(a) In the picture below there are two steps in the ﬂow process. Which of the two steps is
the rate limiting step? In chemistry, the rate limiting step c

1
Chem 1080 workshop 6: Reaction mechanisms
1. Two reaction steps, a slow one followed by a fast one:
(a) In the picture below there are two steps in the ow process. Which of the two steps is
the rate limiting step? In chemistry, the rate limiting step ca

1
Chem 1080 workshop 5: Exponentials
1. The exponential function
Please do these exercises without a calculator.
(a) Evaluating exponents
i. Please evaluate, to whatever number of sig gs you are comfortable with: (0.5)2 ,
(16)0.25 , and (0.125)0.3333 .
ii

1
Chem 1080 workshop 4: Rate laws III
1. Rate-of-reaction laws
(a) Hot popcorn popping is first-order. In a fixed interval of time, the number of popcorn
that pops depends on the number of unpopped popcorn, p. We write the first-order law
as:
p(t) = po ek

1
Chem 1080 workshop 3: Rate laws II
1. Exponents and logarithms (to be solved without a calculator).
(a) Please solve for t.
i.
ii.
iii.
iv.
v.
vi.
vii.
viii.
ix.
x.
xi.
log2 8 = t
log2 217 = t
log2 0.25 = t
(e2.303 )5 = 1000 t
log2 64 = t log8 64
t log9

Worksheet 2.7 Logarithms and Exponentials
Section 1 Logarithms
The mathematics of logarithms and exponentials occurs naturally in many branches of science.
It is very important in solving problems related to growth and decay. The growth and decay
may be t

1
Chem 1080 workshop 2: Rate laws I
The following problems are to be solved without calculators.
1. Exponents and logarithms
(a) Please solve for x.
i.
ii.
iii.
iv.
v.
vi.
vii.
viii.
ix.
x.
xi.
log10 1000 = x
106 = 102 10x
log10 x = 10
1000 102 = x
logx 8

1
Chem 1080 Practice prelim 1-1 2016
This exam has four problems. Problems 1, 3, and 4 are two pages long; problem 2 is on a
single page.
You will be given 90 minutes to complete this exam. The course assistants have been
instructed not to answer any ques

1
Chem 1080 workshop 10: Kinetics review II
1. O2 molecules react in a laboratory with 250 nm wavelength UV photons to form ozone, O3 molecules.
What would you need to do to design an experiment to determine the possible reaction orders in the
above exper

1
Chem 1080 workshop 9: Kinetics review I
1. Please examine the gures below. Each symbol represents 0.10 moles of compound. The containers
are 20.0 L in size. Each arrow represents 5 seconds.
(a) There are no catalysts present in the above reactions. Plea

1
Chem 1080 workshop 11: The Arrhenius equation
1. This problem set uses the Arrhenius equation:
k = Ae
Ea
RT
,
where k is the reaction rate constant, A the pre-exponential factor, and Ea the activation energy.
2. At high pressure, CH2 F2 is a liquid. The

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4. (30 pts) The reaction
is known to have three possible reaction steps:
2 NO(g) r202(g)
N202(g)
k1, kr
+ 02(g) -+ 2 N02 (g)
k2
_where kf and kr refer to the fonvard and reverse rate constants.
In this problem, you will consider three different scenari