Quiz - November 9, 2009
2213 - Heat and E&M
Name:
#:
Show all work clearly and in order, and box your nal answers. Simplify your expressions as
best you can. Use the back of the sheet if you need to. You have 10 minutes to take this quiz.
CONCENTRIC SPHER
Physics 2213
Q29.6
Homework 9 Solutions
Spring 2010
[Magnet & Copper Pipe] Imagine the copper pipe to be made of thin horizontal circular rings piled on top of each other. In the drawing to the right, we show the effect of the falling magnet on a segment
Physics 2213
Homework 8 Solutions
Spring 2010
28.60. We must find the vector sum of the magnetic fields due to each wire. For a long straight wire
B I 0 2r
. The direction of
B
is given by the right-hand rule and is
perpendicular to the line from the wire
Physics 2213
HW #7 Solutions
Spring 2010
#1 [Magnetic Force on a Cable] up (a) The force on the cable due to the Earths magnetic field is F = IL B . The direction will be due South and 30o below the horizontal (see diagram on right). The S N magnitude of
Physics 2213
HW #6 Solutions
Spring 2010
24.14. Let C1 = 15 pF , C2 = 9.0 pF and C3 = 11 pF . The capacitors between b and c, that is C2 and C3, are in parallel. The equivalent capacitance of this combination is C23 = C2 + C3 = 20 pF . The combination C23
Physics 2213
HW #5 Solutions
Spring 2010
26.23. [Kirchoffs Circuit Rules] We have to use Kirchoffs rules to find the unknown currents, emfs, and resistances. Apply the junction rule at points a, b, c and d to calculate the unknown currents. Then apply the
Physics 2213
HW #4 Solutions
Spring 2010
Q25.8 [Batteries] Labeling batteries by emf makes sense because the potential difference across the battery is constant in the ideal case, and nearly constant for real batteries. Labeling batteries by current would
Physics 2213
HW #3 Solutions
Spring 2010
Q23.5
E d l = Va Vb , so if E is zero everywhere along the path, the integral is zero and the potential
b a
difference, Va Vb will be zero. This does not mean that the electric field will be zero everywhere along
Physics 2213
HW #2 Solutions
Spring 2010
21.57 [Two charge sheets] From equation 21.12 in the text, for a uniformly charged infinite sheet, the electric field is E =
E+ a E
+
. Note that this 2 0 is independent of the distance from the sheet. Then Point
Physics 2213
HW #1 Solutions
Spring 2010
#Q21.10 [Metal Objects] Heres one way to do it.
(i)
Put the objects together.
(ii) Bring a charged object near them. This polarizes the touching objects, inducing negative charge on the left, and positive charge on
Physics 2213
Homework 10 Solutions
Spring 2010
Q30.2 [Transformer] Transformers work because of Faraday's Law of magnetic induction a changing magnetic flux produces an induced emf. Since the areas and orientations of the transformer's coils are fixed, a
HW8 Concepts
Alex Alemi
October 21, 2009
1
24.38 Dielectric
This problem leads through an example of Capacitance in the form of a parallel
plate. In particular you are told to calculate the capacity the plates have for
charge at a particular potential. Th
Quiz - November 1, 2009
2213 - Heat and E&M
#:
Name:
Show all work clearly and in order, and box your nal answers. Simplify your expressions as
best you can. Use the back of the sheet if you need to. You have 10 minutes to take this quiz.
CAPACITOR NETWOR
Quiz - November 1, 2009
2213 - Heat and E&M
Name:
#:
Show all work clearly and in order, and box your nal answers. Simplify your expressions as
best you can. Use the back of the sheet if you need to. You have 10 minutes to take this quiz.
CIRCUIT DIAGRAM
Quiz - October 14, 2009
2213 - Heat and E&M
#:
Name:
Show all work clearly and in order, and box your nal answers. Simplify your expressions as
best you can. Use the back of the sheet if you need to. You have 10 minutes to take this quiz.
CONCENTRIC SPHER
2213 - Heat and E&M - 2009
Quiz - 10/07/09
Name:
#:
Show all work clearly and in order, and box your nal answers. Simplify your expressions as
best you can. Use the back of the sheet if you need to. You have 10 minutes to take this quiz.
CHARGED PLATES -
2213 - Heat and E&M - 2009
Quiz - 09/16/09
#:
Name:
Show all work clearly and in order, and box your nal answers. Simplify your expressions as
best you can. Use the back of the sheet if you need to. You have 10 minutes to take this quiz.
POSITIVE AND NEGA
2213 - Heat and E&M - 2009
Quiz - 09/16/09
#:
Name:
Show all work clearly and in order, and box your nal answers. Simplify your expressions as
best you can. Use the back of the sheet if you need to. You have 10 minutes to take this quiz.
COMPARING THERMOD
2213 - Heat and E&M - 2009
Quiz - 09/09/09
Name:
Show all work clearly and in order, and box your nal answers. Simplify your expressions as
best you can. Use the back of the sheet if you need to. You have 10 minutes to take this quiz.
GAS IN A CYLINDER -
HW11 Concepts
Alex Alemi
November 16, 2009
1
28.20 Two Hikers
solenoid diers from an innite one. Can you derive
an expression for the magnetic eld along the axis of
Here you are given the parameters for a transmission a nite solenoid as a function of the
HW9 Concepts
Alex Alemi
November 1, 2009
1
24.28 Capacitor Energy
You are told to consider connecting a charged capacitor together with an uncharged one and told to compute (a) the original charge, (b) nal potential
dierence across each capacitor, (c) the
Physics 2213
28.20.
HW #11 Solutions
Fall 2009
IDENTIFY and SET UP: The magnitude of B is given by Eq.(28.9) and the direction is given by the right-hand rule. (a) EXECUTE: Viewed from above, the current is in the direction shown in Figure 28.20.
Directl
Physics 2213
Homework #7
Fall 2009
Due : the last recitation class of the week of October 19-23. Read: Section 25.4; Chapter 26, sections 26.1-26.3 Chap. 26: Q's #Q26.1, 2, 3, 4, 5, 6, 7, 9, 10, 11, 12 E's & P's: #26.3, 7, 9, 11, 13, 15, 21, 55, 61.
For s
Possibly Useful Information for Electricity and Magnetism : kq1q2 qq = 1 22 2 r 4or kQ Q E= 2 = 2 r 4or Fe = E = 2k = 2o F = qE E= 2k r = 2 r o E
N A
E =
E dA
Qencl
E = 4k =
o
o E dA = 4kQencl =
kQ Q V= r = 4or kq1q2 qq = 12 r 4or V L R = I = A 1 1 1 =
Possibly Useful Information: TF = 5 TC + 32 Ktrans = N 2 mvrms = 2 NkT Q = mc T Q=CT W= p dV
1
2
9
TK = TC + 273
3
pV = nRT = NkT 3RT/M Q = mL H = eA T
4
vrms =
3kT/m =
Q = nC T T -T dQ H = dt = k A H L C f f U = 2 NkBT = 2 nRT W = nRT ln(V2/V1) Cp = CV +
Physics 213
Your Name: Recitation Section #:
FINAL EXAM (12/12/08)
Fall 2008
Recitation Instructor:
Instructions:
Please write your name, recitation section number, and recitation instructor at the top. There are 11 problems in this exam. The total numb