Math 111.01 Summer 2003
Assignment #4 Solutions
1.
Practice problems.
Solutions may be found in the back of the text, or in the Student Solutions Manual.
2.
Extra practice computing derivatives.
Solutions may be found in the back of the text, or in the St
Math 111.01 Summer 2003
Assignment #5 Solutions
1.
I hope you did!
2.
Practice problems.
Solutions may be found in the back of the text, or in the Student Solutions Manual.
3.
Problems to hand in.
Section 4.5
#4.
a. Type 00 indeterminate form.
b. limxa [f
Math 111.01 Summer 2003
Assignment #3 Solutions
1.
Seriously, you should rework all of the problems on Prelim #1, paying special attention
to those that you got incorrect.
2.
Practice problems.
Solutions may be found in the back of the text, or in the Stu
Math 111.01 Summer 2003
Assignment #2 Solutions
1.
Practice problems.
Solutions may be found in the back of the text, or in the Student Solutions Manual.
Section 2.4 #34 Answer: Let f (x) = x2 2. Since f is a polynomial it is obviously continuous.
Since f
Math 111.01 Summer 2003
Assignment #6 Solutions
1.
Practice problems.
Solutions may be found in the back of the text, or in the Student Solutions Manual.
2.
Extra practice.
Solutions may be found in the back of the text, or in the Student Solutions Manual
Math 111.01 Summer 2003
Assignment #1 Solutions
1.
Practice problems.
Solutions may be found in the back of the text, or in the Student Solutions Manual.
Section 1.4 #2 Answer: (d) [2, 10] [2, 6]
2.
Problems to hand in.
Section 1.1
#8. It is a function. I
Math 111.17 Fall 2002
Assignment #11 Solutions
3. (a) Let f (x) = x3 + 3x 2k. Then Newtons method tells us
xn+1 = xn
f (xn )
.
f (xn )
Since f (x) = 3x2 + 3, substituting yields
(x3 + 3xn 2k)
n
(3x2 + 3)
n
2 + 3)x (x3 + 3x 2k)
(3xn
n
n
n
=
(3x2 + 3)
n
2
Math 111 Prelim #2 Solutions - July 21, 2003
1.
(a) f (x) = ex cos(ex 1)
(b) f (x) =
x
x2 + 1
x
ln(x), so f (x) = 1 ln x + 1 .
2
2
2
(c) f (x) = 0 since e e is a constant.
(d) f (x) =
2x sec2 x 2x ln 2 tan x
sec2 x ln 2 tan x
=
22x
2x
2.
(a) We can use t