Wise 1
Kimberly Wise
Lab 4: Newtons Three Laws
February 11, 2016
Group Members:
Amanda Jones,
Benjamin Borden,
Susan Mulaharn
Wise 1
Introduction
Newton had three laws regarding objects traveling with small velocities. Newtons first
law, also called the L
Kimberly Wise
Lab 3: Projectile Motion
February 4, 2016
Group Members:
Amanda Jones,
Susan Mulaharn
Benjamin Borden
Tyler Edge
Introduction
Projectile motion is the motion that an object has when it is launched from some initial
height and travels some di
Wise 1
Kimberly Wise
Lab 2 Report: Inclined Planes
1/28/2016
Group Members:
Amanda Jones
Tyler Edge
Benjamin Borden
Susan Mulaharn
Wise 2
Introduction
Inclined planes are often used to help elevate materials or objects. The force on an
inclined plane that
Kimberly Wise
Lab 6: Ohms Law
10/6/16
Lab Partners:
Abigail Clemens,
Irene Cervantes,
Elena Pradhan
Introduction
Ohms law regards a current passing through a conductor that is between two measured
points. It states that the current is proportional to the
Kimberly Wise
Lab 3: Electric Fields
September 22, 2016
Group Members:
Abby Clemons,
Irene Cervantes, and
Elena Pradhan
Introduction
Electric fields come about because of charges. A charge can have either a positive or a
negative charge associated with it
Wise 1
Kimberly Wise
Lab 1: Pendulum Experiment
January 21, 2016
Group Members:
Amanda Jones,
Susan Mulaharn
Benjamin Borden
Wise 2
Introduction
The purpose of this experiment was to determine what affects the period of a pendulum.
A normal pendulum was c
Kimberly Wise
Lab 7: RC Circuits
10/20/16
Lab Partners:
Abigail Clemens,
Irene Cervantes,
Elena Pradhan
Introduction
Capacitors are capable of storing electric charges. This means that they have the ability to
charge and discharge electric current. When c
1. Conservation of momentum requires that the gamma ray particles move in opposite directions with momenta of the same magnitude. Since the magnitude p of the momentum of a gamma ray particle is related to its energy by p = E/c, the particles have th
1. If R is the fission rate, then the power output is P = RQ, where Q is the energy released in each fission event. Hence, R = P/Q = (1.0 W)/(200 106 eV)(1.60 10 19 J/eV) = 3.1 1010 fissions/s.
2. We note that the sum of superscripts (mass number
1. Our calculation is similar to that shown in Sample Problem 42-1. We set K = 5.30 MeV=U = (1/ 4 0 )( q qCu / rmin ) and solve for the closest separation, rmin:
rmin
-19 9 q qCu kq qCu ( 2e )( 29 ) (1.60 10 C )( 8.99 10 V m/C ) = = = 4 0 K 4 0 K
1. The number of atoms per unit volume is given by n = d / M , where d is the mass density of copper and M is the mass of a single copper atom. Since each atom contributes one conduction electron, n is also the number of conduction electrons per unit
1. (a) For a given value of the principal quantum number n, the orbital quantum number ranges from 0 to n 1. For n = 3, there are three possible values: 0, 1, and 2. (b) For a given value of , the magnetic quantum number m ranges from - to + . For =
1. According to Eq. 39-4 En L 2. As a consequence, the new energy level E'n satisfies
En L = En L
FG IJ = FG L IJ H K H L K
-2
2
=
1 , 2
which gives L = 2 L. Thus, the ratio is L / L = 2 = 1.41.
2. (a) The ground-state energy is
( 6.63 10
1. (a) Let E = 1240 eVnm/min = 0.6 eV to get = 2.1 103 nm = 2.1 m. (b) It is in the infrared region.
2. The energy of a photon is given by E = hf, where h is the Planck constant and f is the frequency. The wavelength is related to the frequency b
1. From the time dilation equation t = t0 (where t0 is the proper time interval,
= 1 / 1 - 2 , and = v/c), we obtain
= 1-
FG t IJ . H t K
2 0
The proper time interval is measured by a clock at rest relative to the muon. Specifically, t0 = 2.2
1. (a) The flux through the top is +(0.30 T)r2 where r = 0.020 m. The flux through the bottom is +0.70 mWb as given in the problem statement. Since the net flux must be zero then the flux through the sides must be negative and exactly cancel the tota