Problem Set 2
SHOW ALL WORK!
1) In the game of monopoly, the number of spaces a token is moved forward is
determined by the sum of the two dice that have been rolled. The outcome of interest is
the nu
TUFTS UNIVERSITY
Economics 13
Statistics
Fall Semester 2013-2014
Professor Downes
Solutions to Problem Set 2
1) Since the sum of two dice must be between 2 and 12, the sample space for this
experiment
TUFTS UNIVERSITY
Economics 13
Statistics
Fall Semester 2013-2014
Professor Downes
Solutions to Problem Set 1
1) a) The mean value per acre is $3909.524. Since there are 21 observations, the median
is
TUFTS UNIVERSITY
Economics 13
Statistics
Fall Semester 2013-2014
Professor Downes
Problem Set 1
Due Date: September 23
HOW ALL WORK!
1) The accompanying table contains the 2013 value per acre of farml
EC 13: Stats Problem Set 2
1. The sample space for the Monopoly experiment in which two dice are rolled and a
token is moved the number of spaces equal to the sum of the numbers on the two
dice. There
EC 13: Stats
Problem Set 3
1.
a. The probability that after 3 days the stock will be at its original price is 0,
as the sample space only includes: an increase of 3 from original price, an
increase of
Solutions to 1st Midterm Examination 1) a) The histogram that corresponds to this sample is:
b) To find the mean, we must use the formula
K
X = (
f k mk
k =1
)/N ,
where mk is the midpoint of th
Problem Set 10
Problem 1
a) indepvar= #of miles per week
b) see graph
c) see graph
d) r=-0.9601
negative correlation, meaning with the increase of number of hours run in a
week, 1mile time run on Su
TUFTS UNIVERSITY
Department of Economics
EClB, Statistics, Spring 2009, Prof. M. Bianconi, March 30, 2009
MID-TERM II ONEHOUR EXAM
l TA Name:
LAJ._
Answer all T en Questions (I 0 points
Ec13 Statistics lA-IB
Recitation l/29/09
0. Note that the data for the STATA part ofthe Problem Set 1 is in Excel. You have to
copy and paste into Data Editor ofSTATA. To open Data Editor, Click on t
EC 13: Stats
Problem Set 4
1.
a. I found the probability distribution of X by using the method of 4
choose 0 (times) 12 choose 4 (divided by) 16 choose 4, 4 choose 1 (times)
12 choose 3 (divided by) 1
EC 13: Stats
Problem Set 5
Recitation: Thursday @ 7:30
1. Using Table D5 I found:
a. =.1001
b. (alternately 1-P(x 1)=.9536
c. =.0034
d. =.5078
2. n=16 p=.65 x=10
a. P(x 10)-P(x 9)=.1982
b. 1-P(x 11)=.
Ec13
Stats Problem Set 6
1.
a.
b.
c.
d.
See attached
5*.1*.5=.25
1-(.08*.4*.5)=.84
0, it is continuous
2.
a. 1/7*(5.25-2.5)= 11/28
b. 5/7 5*1/7
c. 7+0/2=3.5
3.
a. see attached
b. (2.15/4)-(.75/4)=1.4/