3/31/2008 ME 145 - Solution to Supplemental Problem 5
m 1000
p 15MPa
v f 15MPa 0.00165
f
Natural buoyancy pressure rise pB gH f R
1 606.1 vf
pdrop
9.812606.1 300 3.6 x104 Pa 0.036MPa 0.1MPa Pump Needed p pump 0.1 - 0.0
3/8/2008 ME 145 - Solution to Supplemental Problem 5
m 1000
p 15MPa
v f 15MPa 0.00165
f
Natural buoyancy pressure rise pB gH f R
1 606.1 vf
pdrop
9.815606.1 250 5.23 x104 Pa 0.0523MPa 0.06MPa Pump Needed p pump 0.06 -
1/26/2008 ME 145 - Solution to Supplemental Problem 2 Powerfc = Power rating/DC to AC efficiency = 2x106/0.80 = 2.5 MW(e) DC Assume 0.8 V output (unrealistic but the numbers will work to give a reasonable estimate) Powerfc = V x I = 0.8 x I = 2.5x106
2/6/2008 ME 145 - Solution to Tester Text Problem 15.2
3.2 x1012 x1000 Average power needed in Watts 3.65 x1011 24 x 365.25
Power provided in Watts CFxN T x500x1000 0.25 x500x1000xN T 125000N T Where CF=Capacity Factor and NT=number of wind tur
2/13/2008 ME 145 - Solution to Tester Text Problem 14.2
Part a
P COP
Part b PROS:
3 AcVavg
2
0.3
1025xx 170 2
x2 2
2
3
27.9 x106 W(e) 28 MW(e)
higher energy density than wind 40 units 1000 MW(e) no visual pollution predictable c
ME 145 POWERPLANT ENGINEERING ANALYSIS AND DESIGN In-Class Midterm Exam
SPRING 2004
NAME: 1. (3) Fuel cells are limited by the Carnot efficiency true or false? Explain your answer. False. The Carnot limit is applicable to a heat engine that opera
Department of Mechanical Engineering ME 145 Power Generation Systems - Spring 2008
In-Class Midterm Exam 20 points total
Allowed Materials: Tester et al. text and one 8 x 11 sheet. PLEASE WRITE ANSWERS & SHOW WORK ON THESE SHEETS. USE BACK IF NECE
2/17/2008 ME 145 - Solution to Problem 10.3 of Tester et al. Text 12x106 people x 2 lbm/day x 0.5 x 7500 BTU/lbm = 9x1010 BTU/day 9x1010 BTU/day x 365.25 days/year = 3.29x1013 BTU/yr 3.29x1013 BTU/yr x (1/9.48x1014) EJ/BTU = 0.035 EJ/yr % increase =