ECE 361
Homework VI Solution
Hint: some of the designs may require the use of more than one OpAmp.
1. Design an OpAmp circuit with a voltage gain of 5 and input
impedance of 10 k.
A Solution:
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R1

OP
AMP
10k
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+
U1
Rout
Vin
2. Design an OpAmp
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University of Massachusetts at Amherst
ECE 361 EXAM #1  Fall 2016
 PRACTICE EXAM NAME:_
Instructions:
This is a 50 minute closedbook, closednotes exam. You may use one doublesided sheet of
notes and formulas as a reference during this exam.
Calcul
Problem 1. A given npn transistor has P = lOO, ls = SOA, and lc = 3mA. Based on this
information, determine the region of operation (10 points)
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(a) Active
b
);: 5 (0. = 5,tt
') Xe.
(e) Analog
(d) Digital
(b) Cutoff
Problem 2. What
University of Massachusetts at Amherst
ECE 361 EXAM #1  Fall 2016
 PRACTICE EXAM 
NAME: SOLU 7 ()10
Instructions:
' This is a 50 minute closedbook, closednotes exam. You may use one double~sided sheet of
notes and formulas as a reference during this
It
7. In this problem, you areto determine the load voltage V1. for two different values
of the base resistor Rain the transistor circuit shown. The npn transistor In this
circuit has [3: 30. Justify any assumptions you make.
+5V +5V
_ 5"? f : SIH
Abstract
The United States has long been a leader in nuclear energy, but in recent years, nuclear
energy has been largely ignored in favor of other energy sources. Most of the funding for nuclear
energy besides those with military use have received budget
ECE 361
Fundamentals of Electrical
Engineering
University of Massachusetts
at Amherst
Fall 2016
Professor McLaughlin
Lecture #3 9/12/16
Finish reading Chapter 1
Week 2
Read Chapter 2, Sections 2.1  2.4
Work on Homework Set #1
Form your 2person lab team.
1)P=4*.03=.12W
.12J/s
4V*5kJ=20 KJ
T=20KJ/.12=46.3 hrs
C.
2) 4V out of the op amp > 2V over the LED
V/R=13mA
A
3) Voltage divider problem
VB=4*5/(10+5)
=1.33 V
C
4) (15+15)^1 +(25+25)^1=20
B
5) i=(VAVB)/10k
(515)/10^4
=.001
A
6) (29)/100 +(29)/100=
ECE361
Fall 2016
Team Members:
Team Number:
Team Name:
Mentor Name:
Lab Assignment #1
What to Submit: Each group member is to complete this form, filling in the information in the
locations provided, and submit via Moodle. Also submit a photo of Activity
ECE 361 Fall 2010
Exam I
The exam format is, closed book, closed notes, calculators allowed, no
computers. Cell phones are not to be visible. Of the ten problems, compete
seven of your choice. I will grade the first seven problem numbers that you have
cir
ECE 361 Fall 2010 Exam II
Name
.
Choose to answer problem 1 or 2, then answer all of the remaining.
1. For the circuit below the switch closes at t = 0. The source V is DC
(V(t) = V0). Find the expression for the inductor current as a
function of time.
TC
Exam III Practice Problems
Note: These problems are additional material and in no way are an
example of the entire exam. You are still responsible for the concepts
covered in homeworks VI & VII and quizzes 7 & 8.
1. Design an OpAmp circuit with Vout = (Vi
ECE 361
Homework VI
Hint: some of the designs may require the use of more than one OpAmp.
1. Design an OpAmp circuit with a voltage gain of 5 and input
impedance of 10 k.
2. Design an OpAmp circuit with a gain of 10 and input impedance
as large as poss
ECE 361 LaPlace Notes
Definition of the Laplace Transform
L [f[t] = f [ s] = f [t ]e st dt
0
Assumptions:
1. f[t] = 0 for t < 0
2. we = wm = 0 at t = 0
Useful properties of the Laplace Transform
Linearity:
L [a f[t] + b g[t] = af [ s ] + bg[ s ]
Different
ECE 361 Fall 2011
Homework V
1. Find the transfer function between the voltage source, V(t), and the
inductor current, I(t), for the circuit below.
R1
I(t)
+
L1
V(t)
R2
Solution: By KCL the current through R1 must equal the sum of the
currents through R2
ECE 361 Fall 2011
Homework I Solutions
1. 1.36
ia = ib = 2A
ic 3A + ib = 0 > ic = 1A
id ie 3A = 0 > id = 4A
2. 1.37
ic ib + ia = 0 > ic = 1A
if id ia = 0 > if = 3A
ic ie + ih = 0 > ie = 5A
ig if + ih = 0 > ig = 7A
ie + ig id  ib = 0 > ib = 3A
ECE 361 Fall 2011
Homework III Solutions
1. You have five resistors connected in parallel with values of 1, 2, 3, 4, and
5. The current through the 1 resistor is 1A.
a) What is the current through the 4 resistor?
b) What is the total current entering the
ECE 361 Fall 2011
Homework IV Solutions
1. For the circuit below, VC(0)=10V and the switch closes at t = 0.
Find when VC = 5V.
VC
+
C
10k
Solution: With the switch closed we can write a KCL equation for the
node at the top.
CV +
V
V
= 0 V =
10k
C10k
From
Solutions to RC and RL circuits with inductor networks
Example One
Consider the circuit of Figure One with the switch opening at t=0.
R1
U1
I1(t)
+
I3
L1
V0
I3
R2
L2
Figure One
We seek the function I1(t) for all time. Steady state analysis for t<0 revels
University of Massachusetts Amherst Department of Electrical and Computer Engineering ECE 361 Fundamentals of Electrical Engineering Spring, 2008 Handout #6  Natural Responses of RC and RLCircuits (Feb. 19)
Natural Responses of RLCircuits (Feb.