SOLUTION
Using the force triangie and the Law of Cosines 7 . r, 5 .I, .
R2=00bf+Q0bYZQMMQOEmHW
=[1004400400(0342[pb2 ~
= 636.81?)Z
R=m
Using now the Law of Sines
1011:. _ 25.231b
sin sin¥10°
m=(£:;Jmnm°
= 0.3724
So: 7 = 21.87°
Angle of inclination
CEE260/MIE273
Homework #1
Problem 1.
a.
feed
horsebean
soybean
mean
174.9
246.2
b.
feed
horsebean
soybean
mean
174.9
246.2
median
160
248
The horsebean sample has a skewed distribution, while the soybean sample has a more symmetric distribu
tion.
c.
feed