STAT3010 Homework 6 Solution
March, 28, 2016
Problem 1: 2 is better. Since both estimators are unbiased, the variance of estimator
2 is smaller.
Problem 2:
E(1 ) = no bias; V ar(1 ) = 12 = M SE(1 )
E(2 ) = no bias; V ar(2 ) = 10 = M SE(2 )
E(3 ) 6= bias;
Homework Solution
7.14.
(a)
A 95% two-sided confidence interval for the true average dye-layer density for all such trees is:
s
x 1.96
n
.163
1.28 1.96
69
1.028 0.03846
.9895,1.0665
1.96s
(b) n
B
2
1.96.16
.025
2
158
A sample size of 158
Chapter 2: Numerical Summary Measures: June 9, 2014
1
Brice Nguelifack Summer 2014
1
Additional Summary Quantities and Plots (Section 2.3 & 2.4 in textbook)
(1) Percentiles The median divides a data set into two equal parts. A ner partition can be obtaine
Chapter 3: Bivariate and Multivariate Data and Distributions: June 13, 2014
1
1
Fitting a Line to Bivariate Data (section 3.3)
We rst draw the scatterplot of two quantitative variables for a visual inspection of relationship between
those variables. We th
Chapter 3: Bivariate and Multivariate Data and Distributions: June 11, 2014, B. Nguelifack
1
A multivariate data set consists of observations made simultaneously on two or more variables. One
important special case is that of bivariate data, in which obse
STAT 3010-051
PRACTICE EXAM 3
SUMMER 2014
Problem
The data Set Testscore contains the scores for Midterm and nal of a sample
of students for three dierent consecutive years of Stat3010 : 001, 002, and 003 of
the same University. Here we assume that the sc
STAT 3010-130
PRACTICE EXAM 3
SPRING 2014
Problem
The data Set Testscore contains the scores for Midterm and nal of a sample
of students for three dierent consecutive years of Stat3010 : 001, 002, and 003 of
the same University. Here we assume that the sc
STAT 3010
Project
Wednesday, Jun 18, 2014.
Problem 1: Watch the talk by Malcolm Gladwell on spaghetti sauce (17 minutes) from
the link :
http:/www.ted.com/talks/lang/en/malcolm_gladwell_on_spaghetti_sauce.html
and answer the questions below.
(1) What kind
STAT3010 Homework 5 Solution
February, 26, 2016
Problem 1: Let X be the diameter in microns.
1. X = 1/ = 1/0.25 = 4 microns
2. sX = 1/ = 1/0.25 = 4 microns
3. P (X < 3) = 1 e0.25(3) = 0.5276
4. P (X > 11) = 1 (1 e0.25(11) ) = 0.0639
5. Let m be the median
STAT3010 Homework 4 Solution
February, 23, 2016
Problem 1:
2 = p(1 p) = 0.24
1. X Bernoulli(p), where P = 0.4. X = p = 0.4, X
2. No. No. A Bernoulli random variable has possible values 0 and 1. The possible
values of Y are 0 and 2.
3. Y = 2X, where X Bern
STAT3010 Homework 2 Solution
January, 26, 2016
Problem 1:
1. Event A = cfw_SSF, SF S, F SS
2. Event B = cfw_SSS, SSF, SF S, F SS
3. For Event C, the system must have component 1 working (S in the first position),
then at least one of the other two compone
STAT3010 Homework 7 Solution
April, 11, 2016
= 783, s = 120, n = 73. The The null and alternate hypotheses
Problem 1: X
are H0 : 750 versus H1 : > 750. z = (783 750)/(120/ 73) = 2.35. Since
the alternate hypothesis is of the form > 0 , the P-value is the
STAT3010 Homework 1 Solution
January, 19, 2016
Problem 1: The total height of the 20 men is 20 178 = 3560. The total height of
the 30 women is 30164= 4920. The total height of all 50 people is 3560 + 4920 = 8480.
There are 20 + 30 = 50 people in total. Th
1. A study is conducted on students-taking a statistics class. Several variables are recorueu
in the survey. Select _a_l_| variables that are quantitative (numerical).
A) Type of car the student owns.
(5) Number of credit hours taken during that semester.