STAT3010 Homework 6 Solution
March, 28, 2016
Problem 1: 2 is better. Since both estimators are unbiased, the variance of estimator
2 is smaller.
Problem 2:
E(1 ) = no bias; V ar(1 ) = 12 = M SE(1 )
E(
Homework Solution
7.14.
(a)
A 95% two-sided confidence interval for the true average dye-layer density for all such trees is:
s
x 1.96
n
.163
1.28 1.96
69
1.028 0.03846
.9895,1.0665
1.96s
(b)
Chapter 2: Numerical Summary Measures: June 9, 2014
1
Brice Nguelifack Summer 2014
1
Additional Summary Quantities and Plots (Section 2.3 & 2.4 in textbook)
(1) Percentiles The median divides a data s
Chapter 3: Bivariate and Multivariate Data and Distributions: June 13, 2014
1
1
Fitting a Line to Bivariate Data (section 3.3)
We rst draw the scatterplot of two quantitative variables for a visual in
Chapter 3: Bivariate and Multivariate Data and Distributions: June 11, 2014, B. Nguelifack
1
A multivariate data set consists of observations made simultaneously on two or more variables. One
importan
STAT 3010-051
PRACTICE EXAM 3
SUMMER 2014
Problem
The data Set Testscore contains the scores for Midterm and nal of a sample
of students for three dierent consecutive years of Stat3010 : 001, 002, and
STAT 3010-130
PRACTICE EXAM 3
SPRING 2014
Problem
The data Set Testscore contains the scores for Midterm and nal of a sample
of students for three dierent consecutive years of Stat3010 : 001, 002, and
STAT 3010
Project
Wednesday, Jun 18, 2014.
Problem 1: Watch the talk by Malcolm Gladwell on spaghetti sauce (17 minutes) from
the link :
http:/www.ted.com/talks/lang/en/malcolm_gladwell_on_spaghetti_s
STAT3010 Homework 4 Solution
February, 23, 2016
Problem 1:
2 = p(1 p) = 0.24
1. X Bernoulli(p), where P = 0.4. X = p = 0.4, X
2. No. No. A Bernoulli random variable has possible values 0 and 1. The po
STAT3010 Homework 2 Solution
January, 26, 2016
Problem 1:
1. Event A = cfw_SSF, SF S, F SS
2. Event B = cfw_SSS, SSF, SF S, F SS
3. For Event C, the system must have component 1 working (S in the firs
STAT3010 Homework 7 Solution
April, 11, 2016
= 783, s = 120, n = 73. The The null and alternate hypotheses
Problem 1: X
are H0 : 750 versus H1 : > 750. z = (783 750)/(120/ 73) = 2.35. Since
the alter
STAT3010 Homework 1 Solution
January, 19, 2016
Problem 1: The total height of the 20 men is 20 178 = 3560. The total height of
the 30 women is 30164= 4920. The total height of all 50 people is 3560 +
1. A study is conducted on students-taking a statistics class. Several variables are recorueu
in the survey. Select _a_l_| variables that are quantitative (numerical).
A) Type of car the student owns.