CE 408/Johnson
Computer Assignment #1
Write MATLAB programs to solve the following problems. You may work together in groups of at
most 3 (turn in just one completed assignment for your group).
Problem 1: Using the functions discussed in 6.0 of the MATLAB

2%
Chapter 1, Roles of Probability and Statistics in Engineering
.\ Survey of Progress in House Building. Building iich
(saIl Management. VoL 7(4). April 1969, pp. 88 9!
(san. WI . and Snodgrass. DV. Machine Stress Rated Lumber:
h.d knae to Design, Journa

2
C iapter 2 Fundamentals of Probabdity Models
2.3 Mathematics of Probability
53
For three events, the multiplication rule would give,
pi )
and
P(fr)
7
7
At the intersection, if a vehicle is definitely makine a turn, the probability that it will be a righ

Composite Construction in Steel and Concrete, McGraw-Hill; Chi and
BibersteinTheory of Prestressed Concrete, Prentice-Hall; Connolly
Design of Prestressed Concrete Beams, McGraw-Hill; Evans and
BennettPre-stressed Concrete, Wiley; LibbyPrestressed Concret

3,315,000(0.00067)/12 - 185 Ib (822.9 N), as before. THERMAL
EFFECTS IN COMPOSITE MEMBER HAVING ELEMENTS IN
SERIES The aluminum and steel bars in Fig. 23 have cross-sectional
areas of 1.2 and 1.0 in2 (7.7 and 6.5 cm2 ), respectively. The member is
restrai

stress. Let sx and sy = the principal stress in the x and y direction,
respectively; Sn = normal stress on the plane making an angle 6 with the
y axis; ss = shearing stress on this plane. All stresses are expressed in
pounds per square inch (kilopascals)

Association of State Highways OfficialsA Policy on Geometric
Design of Rural Highways; ChellisPile Foundations, McGraw-Hill;
Goodman and KarolTheory and Practice of Foundation Engineering,
Macmillan; HuntingtonEarth Pressures and Retaining Walls, Wiley;
K

members according to their respective AE values. Thus Af3 (relative) =
0.1105 x 30 x IQ6 = 3315 Af c (relative) = 0.0858 x 15 x IQ6 = 1287
Total 4602 Then the coefficient of thermal expansion of the composite
member is c = (3315c5 + 1287cc )/4602 = 7.2 x

Assume that both reactions are directed to the left. Consider a tensile
force as positive and a compressive force as negative. Consider a
deformation positive if the body elongates and negative if the body
contracts. FIGURE 16 Express the axial force P in

designers to save thousands of hours of calculation time. Yet each
calculation procedure must be programmed, unless the engineer is
willing to use off-the-shelf software. The editor-observing thousands of
engineers over the years-detects reluctance among

FIGURE 22 Thick-walled cylinder under internal and external pressure.
3. Check the accuracy of the results Use the relation ^r1 - s0r2 = [(V2 ^1X(V2 + r\)](p^1 + p2r2). Substituting the known values verifies the
earlier calculations. THERMAL STRESS RESULT

= 0.225 in (5.715 mm) to the right; the displacement of B = 0.225 0.075 = 0.150 in (3.81 mm) to the right. 5. Verify the computed results
To verify this result, compute RR and determine the deformation of bar
3. Thus H*FH = - R1 + 30 + 10 - RR = O; RR = 1

Analysis by Slope-Deflection Method Wind Drift of a Building
Reduction in Wind Drift by Using Diagonal Bracing Light-Gage Steel
Beam with Unstiffened Flange Light-Gage Steel Beam with Stiffened
Compression Flange 1.150 1.156 1.159 1.161 1.163 1.164 1.166

Hill; Timber Engineering CompanyTimber Design and Construction
Handbook, McGraw-Hill; U.S. Department of Agriculture, Forest
Products LaboratoryWood Handbook (Agriculture Handbook 72),
GPO; UrquhartCiv/ Engineering Handbook, McGraw-Hill; Borg and
GennaroA

CONCENTRATED LOAD A cold-drawn steel wire % in (6.35 mm) in
diameter is stretched tightly between two points lying on the same
horizontal plane 80 ft (24.4 m) apart. The stress in the wire is Deflected
position Initial position Assumed center of rotation

encounter pounds per square inch pressure, newton whenever you deal
with a force in pounds, etc. SI Table for a Civil Engineer. Let's say
you're a civil engineer and you wish to construct a conversion table and
SI literacy document for yourself. List the

rotation O9 show the bar in its deflected position (Fig. lie). Establish the
relationships among the three deformations. Thus, by similar triangles,
(AZ1 - A/2)/(A/2 - A/3) = 6/10, or 1OA/! - 16A/2 + 6A/3 = O, Eq. c. 3.
Transform the deformation equation

AD = change in cylinder diameter, in (mm); c = coefficient of expansion
of the cylinder = 6.5 x 10-6/0 F (1.17 x IQ-V0C); D = cylinder internal
diameter before heating, in (mm). Thus AJ- (3/32)/[6.5 x 10-6 (48)1 =
30O0 F (1670C). 2. Compute the hoop stres

2(0.015) = 0.030 in (0.762 mm). Thus, the restraint exerted by the walls
is AZ,W = 0.1123 - 0.030 = 0.0823 in (2.090 mm). 3. Determine the
compressive stress Use the relation s = EkLIL, where the symbols are as
given earlier. Thus, s = 30(106 )(0.0823)/[1

revised to permit faster programming in a computer environment. This
enhances ease of solution for any method usedwork station, portable
computer, or calculator. SI Usage. The technical and scientific
community throughout the world accepts the SI (System

by Moving Concentrated Loads . 1.72
Influence Line for Bending Moment in Bridge
Truss . 1.74 Force in Truss
Chord Caused by Moving Concentrated
Loads . 1.75 Influence Line for Bending
Moment in ThreeHinged Arch . 1.76
Deflection of a Beam under Moving Loa

. 1.28 Reactions at Elastic
Supports . 1.29 Analysis of Cable Supporting a
Concentrated Load . 1.30
Displacement of Truss Joint . 1.31 Axial Stress
Caused by Impact Load . 1.32 Stresses on an Oblique
Plane . 1.33 Evaluation of Principal
Stresses . 1.34 Ho

AREAS Graphical Analysis of a Force System Analysis of Static
Friction Analysis of a Structural Frame Graphical Analysis of a Plane
Truss Truss Analysis by the Method of Joints Truss Analysis by the
Method of Sections Reactions of a Three-Hinged Arch Leng

their relative rigidities. Using the subscripts s and b to T>,TTTT. *
^ j i ^ denote steel and bronze, respectively, we FIGURE 24' ComPund
shafi see that O = T5LJ(JsG5) = W(J,G,), where the symbols are as
given in the previous calculation procedure. Solvi

17,930(169.7)/[1.2(30 x 106 )] - 0.0845 in (2.146 mm). 3. Construct the
Williott displacement diagram Selecting a suitable scale, construct the
Williott displacement diagram as follows: Draw ( b) Displacement
diagram FIGURE 19 (Fig. 196) line Ca parallel

catchments must be accompanied by a Water Cycle Management Study.
The contents of a Water Cycle Management Study, including the
information, reports and modeling required, will vary according to the
type of development and the risks it poses to water qual

either unbound granular, cemented, or a combination of these materials.
Layers are to be a maximum of 200mm thick after compaction.
Unbound granular materials are to consist of gravels or crushed rocks,
and have a grading which makes them mechanically sta

consistent guidelines for the design of engineering works within the
Lithgow City Council Local Government Area, and facilitate the
expeditious processing of engineering plan submissions, construction
approvals, and linen plan releases for subdivisions an

any watercourse, waterbody or drainage depression on the site, or 3. Will
transfer any impact outside the site by treatment in a facility to the
required standard and disposal approved by the consent authority, and 4.
The development incorporates the SCAs

& Maps Mobile GIS ArcGIS Mobile ArcPad ArcGIS Desktop
ArcGIS Engine ArcGIS Explorer Server GIS ArcGIS Server ArcGIS
Server Extensions ArcGIS Mobile GIS Mobile GIS is the expansion of
GIS from the office into the field. Wireless connectivity, geoservices,

Consider the given diagram.
R1= 2.5 is connected in series
R2= 5.1 is connected in series with 3.5 and that are parallel with 1.8
R3= 3.2 is connected in series
Consider the equivalent resistance between R2, 3.5 and 1.8
1
1
1.8 5.1 3.5
0.67
the equivale

Given data:
Porosity of soil A,
nA 0.5
Porosity of soil B,
nB 0.333
Hydraulic conductivity of soil A,
Hydraulic conductivity of soil B,
Cross-sectional area of soil A,
Cross-sectional area of soil B,
The flow rate
q
K A 2 ft/min
K B 1 ft/min
AA 4 ft 2
AB

Given data:
Reservoir water level elevation,
Tank water level elevation,
Pump head,
h1 40 ft
h2 50 ft
hp 30 ft
Water flow rate,
Q 10 ft 3 /s
Length of pipe,
L 2 mile
Pipe material = cast iron
Density of water,
1.94 slug/ft 3
Unit weight of water,
62.4 l

Given data for a circular vertical two-lane highway curve.
Central Angle,
I 38o
Vertical Point of Tangency,
PVT 36 50.00 ft
Width of the lanes,
w 12 ft
Tangent grade,
G1 2.5%
Tangent grade,
G2 1.5%
Design speed of two-lane highway curve,
v 75 mph
Super el

Given data:
Modulus of elasticity of steel,
Es 207 GPa
Modulus of elasticity of E-glass fiber-reinforced polyester SMC,
E p 16 GPa
Density of steel,
s 7.87 g/cm 3
Density of E-glass fiber-reinforced polyester SMC,
p 1.85 g/cm 3
Cost of steel,
Ps 0.80 $/