Stats
02/12/2016
=Population mean
=population standard deviation
x=sample mean
s=sample standard deviation p=population proportion
p^ sample population
TABLE A on PAGE 201 IN NOTES
x~N( , )
z~N(0,1)
z=
~N(0,1)
x
if X is capitalized then Z is capitalized
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Probability Distributions: Histogram, Mean, and Standard Deviation
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Enter Weights in P(x)
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Binomial Probability Distributions
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Standard Normal Distribution: zscores and areas under the curve
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Note: P ( x
Adam Kunz
Stat 3011
Due 2/19/17
6.4
Grade
Grade Point Scores (x)
Probability Distribution
A
4
0.2
B
3
0.4
C
2
0.3
D
1
0.1
6.10
A)
X
P(X)
$80,000
0.7
$50,000
0.2
$20,000
0.1
B) P(x<$50,000) = P(50,000) + P(20,000) = 0.2 +0.1 = 0.3 or 30%
C) =xP(X=x) = .7(8
Adam Kunz
STAT 3011
Due 4/5/17
Q1

Onesample test for population mean
H0: = 3.05 vs. HA: > 3.05

Twosided sample test for Minneapolis worker population mean
H0: = .035 vs. HA: .035

Twosided sample test for Minneapolis housing occupancy mean
H0: = .
Adam Kunz
STAT 3011
HW #4
Due 2/26/17
7.7
A)  A sampling distribution of the sample proportion would have a normal distribution and therefore
have a bell shaped curve.

Mean = p = 0.300
Standard Deviation =Sqr Root(p(1p)/n) = Sqr Root(0.300(10.300/500
By Adam Kunz
STATS 3011
Homework #1
1.28
A) Population: All the students in the school
Sample: 100 students who took the survey
B) The school used inferential statistics when going about the study because surveying the whole school
is too costly and time
Adam Kunz
ACCT 2050
HP Assignment
1)
2) HPs Total Stockholders Equity at October 31, 2014.$ 26,731
HPs Market Value of Equity at October 31, 2014.$33,107,184
3) HPs Retained Earnings at October 31, 2014.$29,164
HPs Retained Earnings at October 31, 2013.$2
Notes for Statistics
3011 University of
Minnesota
Fall 2016
Notes accompanying the Third Edition of
Statistics: The Art and Science of Learning
From Data
by Alan Agresti and Christine
Franklin
Contents
CHAPTER 1: INTRODUCTION1
1. The Basics
1
2. The Role
STAT 3011 Study Guide
MengHsuan Wu
October 12, 2015
Chapter 1
1. Population and sample:
(a) Population: A collection of all units in interest.
(b) Subject: An individual unit of a population.
(c) Sample: An observed subset of the units of a population.
2
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(There are options for cop
9.2
a.
b.
c.
The mean IQ of all students at Lake Wobegon High School is larger than 100.
The alternative hypothesis states that the parameter falls in some alternative
range of values. Here the statement shows that the parameter, mean IQ of all
students a
HW 5
8.2
Savannah Johnson
a. Let the proportion of votes for a candidate in an election b p=.548
The point estimate represents a single value used to guess the parameter. Here, the
sample proportion pp is used to estimate p. Therefore, the point estimate
Savannah Johnson
7.14
a. x = number of years of education for selfemployed individuals in the US
The sampling distribution of the sample mean for n=100 has a mean of 13.6.
3
Its standard error equals
=
= 0.3
n
100
The mean and standard deviation of the
HW 1 Savannah Johnson
1.16
a. Flipping the coin 500 times and observing all heads would be
more surprising than flipping a coin 5 times and observing all
heads. This is because when the sample size increases, the
prediction becomes more reliable.
b. I wou
STATS HW 2
Savannah Johnson
1.
a. Sample space: (Ben Carson, Bernie Sanders, Donald Trump,
Hillary Clinton, Marco Rubio, Ted Cruz, Other)
b.
table(president,political.position)
political.position
president
Conservative Liberal Moderate
Ben Carson
13
4
12
Savannah Johnson
6.10
a.
X
P(X
)
0.70
$80,00
0
$50,00
0
$20,00
0
0.20
0.10
b. p=P(50,000_+P(20,000)
=0.20+0.10
=0.30
This means that the probability that the profit is equal or less than $50,000 is 0.30
c. Mean of probability =80,000x0.70+50,000x0.20+20,0
First Pages
Preface
We live in a world that is global, highly competitive, and
increasingly influenced by information technology, particularly the Internet. The first edition of our text Essentials
of Marketing Research became a premier source for new
and
5.2
a) My friends claim is wrong because all probabilities for the possible outcome must equal
one and there are only two possible outcomes in this instance making it a 0.5 probability
for heads and a 0.5 probability for tails. Also, he should run a large
6.4 (p275)
a)
X P(X)
4 0.20
3 0.40
2 0.30
1 0.10
b) 4(0.20) + 3(0.40) + 2(0.30) + 1(0.10) = 2.7. This mean reflects what we expect for the long run
average of the observations.
6.10 (p275)
a)
X
P(X
)
$80,00 0.70
0
$50,00 0.20
0
$20,00 0.10
0
b) The prob
1.28
a) The sample and population is 100 students at the school.
b) The main purpose of descriptive statistics is to reduce the data to simple summaries without
distorting or losing much information. Graphs and numbers such as percentages and
averages are
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Descriptive Statistics:
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StatCrunch Help
Estimating Population Proportions
Confidence Interval:
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Select Confidence Interval, entering appropriate value, and use
Finding probabilities for the standard normal distribution Z N ( 0,1 ) :
Using the ztable
Look for the probability that corresponds to the zscore of z* in the table.
P ( Z < z)
P ( Z > z)
Rewrite the expression as 1P ( Z < z ) , and then look for P ( Z