Stat 5411
Fall 2012
Exam 2
Answers
(1) (a)
(b)
(c)
(2) The difference between strengths of pine and fir boards are the same for all glues. Or equivalently, the
differences between strengths of the 3 glues are the same for pine and fir. How glues compare t
Stat 5411
Midterm 1, Fall 2013
Name
Instructions: You have 50 minutes to complete this exam. Write answers in the space provided below
each question. If you need more room, you can use the back of the page, but clearly indicate where this
is done. Display
Stat 5411
Midterm 1 Solution, Fall 2013
Name Dr. Solution
1. The recipe for producing a high-quality cement species that the required percentage of SiO2 is 6.2%.
A quality control engineer evaluates this specication weekly by randomly selecting samples fr
Practice Exam 1 Part 2
1. Monamine oxidase (MAO) is an enzyme that may aect human behavior. To determine
if dierent types of schizophrenic patients have dierent levels of MAO in their blood, researchers collected blood samples from a simple random sample
Stat 5411 - Analysis of Variance (Fall 2013)
Exam 2 Practice
1. A manufacturer conducted a small pilot study of the eect of the price of one of its
products on sales of this product in hardware stores. Since it might be confusing to
customers if prices we
Stat 5411 - Analysis of Variance (Fall 2013)
Homework 1 Solution
1.
This is an observational study.
There is no active intervention on shoppers from the student. The student simply
interviewed and observed the shoppers.
This is a retrospective study. T
Stat 5411 - Analysis of Variance (Fall 2013)
Homework 2 Solution
1.
(a) False
(b) True
(c) False
(d) False
(e) False
(f) False
(g) False
2.
s
71
(a) The condence interval is y z0.025 n = 110 1.96 .50 = (108.03, 111.97).
(b) We are 95% condent that the ave
Stat 5411 - Analysis of Variance (Fall 2013)
Homework 4 Solution
1.
(a) F0.05,df1 =4,df2 =13 = 3.18 (on page 1185).
(b) F0.01,df1 =10,df2 =90 = 2.52 (on page 1191).
(c) The value of F such that Pr(Fdf1 =5,df2 =20 < F ) = 0.975 is F = 3.29 (on page 1187).
Stat 5411 - Analysis of Variance (Fall 2013)
Homework 5 Solution
1. The standard CI is z/2 (1n ) = 0.10 1.96 (0.10)(0.90) = (0.0412, 0.1588).
100
In WAC CI, y = y + 2 = 12, n = n + 4 = 104, and = y /n = 12/104 = 0.1154. So the
WAC interval is z/2 (1
Stat 5411 - Analysis of Variance (Fall 2013)
Homework 6 Solution
1.
(a) H0 : all incentive plan yield equal productivity versus Ha : at least one incentive plan
yields diering productivity.
(b) The p-value on the ANOVA table is 0.118 > 0.05. This means th
Stat 5411 - Analysis of Variance (Fall 2013)
Homework 7 Solution
1.
(a) Assign the numbers 1, 2, 3, 4, 5 to the plots on each farm. Separately for each farm,
obtain a random ordering of the numbers 1, 2, 3, 4, 5. The plot with the rst number
on the list i
Name _
Stat 5411
Fall 2012
Exam 1
In problems where you need to choose form numbered choices, you can just circle your choice and then briefly
explain why.
For some questions you may leave answers as unsimplified numerical expressions. The expressions
cou
Stat 5411
Fall 2012
Exam 1
Answers
(1) (a) The biggest problem is that there is no replication. We don't have replicate measurements under the same
treatment conditions which would allow us to see how precisely we have estimated the energy costs with and
Name _
Stat 5411
Fall 2012
Exam 2
For some questions you may leave answers as unsimplified numerical expressions. The expressions
could include mathematical notation such as
, Log10(45) , 102.07 etc. For example
y
(1.2 y ) 2 (1.3 y ) 2 (1.8 y ) 2
1.2 1.3