Week Two Discussion
Based on the instructions given, my and compound inequality is
-1 < 3 + 2x < 17
3 + 2x must be greater than or equal to 1 and at the same time it has to be less than 17.
Therefore,
-1 < 3 + 2x < 17
-3
-3
-3
Subtract 3 from all parts of
Week Two Discussion
Based on the instructions given, my and compound inequality is
-1 < -3 + 2x < 17
-3 + 2x must be greater than or equal to 1 and at the same time it has to be less than 17.
Therefore,
-1 < -3 + 2x < 17
+3 +3
+3
Subtract 3 from all parts
Week Three Discussion One
Based on the required reading and the assignment I was given problems #78 and #70 on
page(s) 576-577 (Dugopolski, 2012).
#78
(416)1/2
4(16*1/2)
The problem; I will use the power of a power rule/product
rule
Multiply the exponents
The last letter of my first name is N. So the problems I was assigned to are 78 and 70 on page
576 in our textbook.
78) (416)1/2
my first problem, I will use the product rule (power rule). What this means is
that the based number (4) remains the same, whi
Since a little boy I have always dreamed of owning a boat and now the day has come where I
can officially fulfill my dream. The boat cost is 25,000 dollars and the interest rate on the boat is
8% I will use this amount for the boat and interest rate to de
1Running Head: Two-Variable
Inequality
Two-Variable Inequality
Marcus Wilson
MAT 221
Instructor Justin Hazel
9/22/14
2Running Head: Two-Variable
Inequality
The purpose of this assignment is to write an inequality that limits the possible number of maple
r
Week Five Discussion
Based on the discussion guidelines, I am was assigned #8 and #64 from our required
reading.
#8
y = -3x +4
4
Given function
We know the y-intercept is (0,4) and the slope is -3/4 with a domain of () and a range of
(-) because any real
These are my given rational expressions
2
6g 55/ g
k3 + k/ k2 + k 42
As we can see the domain of a rational expression is the set of all numbers, which are
permissible to alternate for the variable in the expression. It is probable that some
numbers will
There is another way this problem can be solved by completing the square, but my
assignment requires me to solve by factoring. Page 635 problem 4:
1.) w2 2w = 15
w2 + 3w - 5w - 15 = 0 Factor +1 out of all terms
(w2 + 3w) - (5w - 15) = 0 Divide both sides