or, how cats survive falls from
Know: what terminal velocity means
Understand: why falling things reach a terminal
Be able to: describe and explain the stages in a
parachute jump (including the for
Describe the motion at
each stage of the skydivers
Explain why her motion is the
way it is (think about the forces):
Stage 1: at the moment of
leaving the plane
Stage 3: terminal velocity
Term 2- Quiz 1
Duration 45 minutes
I-Choose the best answer
[6 marks, 1 each]
Page 1 of 6
3. Ball X is released to fall down the same time as ball Y i
Practice: Static and Kinetic Friction
1. Gwen exerts a 36-N horizontal force as she pulls a 52-N sled across a cement sidewalk at
constant speed. What is the coefficient of kinetic friction between the sidewalk and the metal
sled runners? Ig
Identify the choice that best completes the statement or answers the question.
1. Which of the following is the tendency of an object to maintain its state of motion?
Uniform and nonuniform motion
3. The person is motionless. b. Equally spaced imaes show her moving
at a constant speed.
if? a}; m;
6. She is speeding up. d. She is slowing down.
Figure 1 The distance the jogger moves in each time i
Chapter 3. Crystal binding
and elastic constants
Crystal binding and mechanical
Why do atoms form crystals or solids?
Answer : Interatomic forces + Pauli principles
Atoms bind due to the Coulomb attractive and repulsive
forces between electrons
Intercollege PHYS-110 FALL 2010 HOMEWORK 1 Instructor: Dr. Phanourios Tamamis Date Posted: 01/10/10 Deadline: 04/10/10
3. Estimate the time needed for a car to travel a distance of 30 m by the time it starts moving given that its acceleration is con
P H Y S1 0 0 4 P h y s i c s 1 ( E n v i r o n m e n t a l ) So l u t ions to A ssig n m e n t 1 ( E l e c t r i c i t y & M a g n e t is m)
C h a r gi ng a C on d u c t i n g R o d
D esc r i p t ion : This problem explores the behaviour of charge on cond
UNIT II READING: MOTION MAPS
A motion map represents the position, velocity, and acceleration of an object at various clock readings. (At this stage of the class, you will be representing position and velocity only.) Suppose that you took a stroboscopic p
1.63: Assume each person sees the dentist twice a year for checkups, for 2 hours. Assume 2 more hours for restorative work. Assuming most dentists work less than 2000 hours per year, this gives 2000 hours 4 hours per patient 500 patients per dentist.
Circular Motion and Other Applications of Newton's Laws
6.1 Newton's Second Law Applied to Uniform Circular Motion Nonuniform Circular Motion Motion in Accelerated Frames Motion in the Presence of Resistive Forces Numerical Modeling
Motion in Two Dimensions
4.1 4.2 4.3 4.4 4.5 4.6 The Position, Velocity, and Acceleration Vectors Two-Dimensional Motion with Constant Acceleration Projectile Motion Uniform Circular Motion Tangential and Radial Acceleration Relativ
3.1 3.2 3.3 3.4 Coordinate Systems Vector and Scalar Quantities Some Properties of Vectors Components of a Vector and Unit Vectors
ANSWERS TO QUESTIONS
Q3.1 No. The sum of two vectors can only be zero if they are in opposit
Physics and Measurement
1.1 1.2 1.3 1.4 1.5 1.6 1.7 Standards of Length, Mass, and Time Matter and Model-Building Density and Atomic Mass Dimensional Analysis Conversion of Units Estimates and Order-ofMagnitude Calculations Signific
CHAPTER 12 Static Equilibrium; Elasticity and Fracture 1. From the force diagram for the sapling we can write ?Fx = F1 F2 sin 20 F3 cos = 0; 380 N (255 N) sin 20 F3 cos = 0, or F3 cos = 293 N. ?Fy = F2 cos 20 F3 sin = 0; F3 sin
CHAPTER 11 General Rotation 1.
z (a) For the magnitudes of the vector products we have i i = i i sin 0 = 0; k j j = j j sin 0 = 0; j k k = k k sin 0 = 0. y (b) For the magnitudes of the vector products we have i j = i j sin 90 = (1)(1)(1
CHAPTER 7 - Work and Energy 1. 2. 3. The displacement is in the direction of the gravitational force, thus W = Fh cos 0 = mgh = (250 kg)(9.80 m/s2)(2.80 m) = 6.86 103 J. The displacement is opposite to the direction of the retarding force,
CHAPTER 4 - Dynamics: Newton's Laws of Motion 1. We convert the units: # lb = (0.25 lb)(4.45 N/lb) ~ 1 N. If we select the bike and rider as the object, we apply Newton's second law to find the mass: ?F = ma; 255 N = m(2.20 m/s2), which
CHAPTER 3 - Kinematics in Two Dimensions; Vectors 1. We choose the west and south coordinate system shown. D 2x For the components of the resultant we have W RW = D1 + D2 cos 45 D 2y D 2 = (200 km) + (80 km) cos 45 = 257 km; RS = 0 + D2 =
CHAPTER 2 - Describing Motion: Kinematics in One Dimension 1. We find the time from average speed = d/t; 15 km/h = (75 km)/t , which gives
t = 5.0 h. 88 km/h.
We find the average speed from average speed = d/t = (280 km)/(3.2 h) =
CHAPTER 9 - Linear Momentum and Collisions 1. We find the force on the expelled gases from F = ?p/?t = (?m/?t)v = (1200 kg/s)(50,000 m/s) = 6.0 107 N. An equal, but opposite, force will be exerted on the rocket: 6.0 107 N, up. For the mome