Physics 210: Epic of Evolution
Homework #1: Solutions
1. Astronomers have deduced that ordinary stars can serve as standard candles, up to
a point. By measuring carefully the different colors in the spectra of stars, they can
classify them into various ty
Physics 210: Epic of Evolution
Homework #4: Solution
Name/Student ID: _
From working out the theory of stellar structure and evolution for low mass stars like
the Sun, astrophysicists have come up with a simple formula that relates the intrinsic
luminosit
Physics 210: Epic of Evolution
Homework #2: Solutions
Name/Student ID: _
In the period prior to Big Bang Nucleosynthesis (BBN), neutrons are created in
collisions between protons and electrons, but they also decay back to protons and
electrons with a half
Physics 210: Epic of Evolution
Homework #3: Solution
Name/Student ID: _
Stars have been observed at a distance of 180,000 light years from the center of the
Milky Way, orbiting around the galaxy with velocities of 250 km/s. Newtonian
gravity says that, fo
P hysics 318 Solution f or P roblem Set 4 1. (a)an atom with three p-shell valence electrons l1 = l2 = l3 = 1, and s1 = s2 = s3 = 1 2 assume l = l1 + l2 |l1 l2 | l |l1 + l2 | 0 l 2 and l3 = 1,0 l + l3 3 0 l 3 so l can be 0, 1, 2, 3 Notation: a lot of stud
P hysics 318 Solution f or P roblem Set1 Each subsection counts for 10 points, if you have questions, please come to my oce crow 220, or send me email [email protected], I think my oce hour is Monday 12-1pm, if this time is not good for you ,you are a
P hysics 318 Solution f or P roblem Set 6
1. See above. 2. (a) from the problem that the Fermi energy of aluminum is 11.63 ev at low temperature, low temperature means that T 0 1
and for free electrons, they are fermions, so the mean number of free electr
P hysics 318 Solution f or P roblem Set 10 1. From the problem, the 0 has a mass m of approximately 135M ev/c2 So, m0 c2 = 135M ev mc = c 197.3M ev 1015 m = 1.463 1015 m = 2 m0 c 135M ev
While the fermi is dened as 1015 meters. So the range is the order o
P hysics 318 Solution f or P roblem Set 9 1 When k near the origin, that means k 0 2 (k a)2 using Taylor expansion, cos(kx a) 1 (kx2a) + . . ., cos(ky a) 1 y2 + . . ., cos(kz a) 1
(kz a)2 2
+ .
l
(kx a)2 (ky a)2 (kz a)2 +1 +1 ] 2 2 2 2 2 2 kx + ky + kz 2
P hysics 318 Solution f or P roblem Set7 1 The maximum value of f (x) = and f (x) = x3 df (x) is given by = 0. ex 1 dx
xex = 0 x 2.82 that means h = 2.82kB T 2.82kB T At T = 2.7K , = = 1.59 1011 s1 h
(ex 1) 3x2 ex x3 = 0 3x2 (ex 1) x3 ex = 0 3ex 3 (ex 1)2
P hysics 318 Solution f or P roblem Set 8 1. rate=number of simulated emissions/per second. rate = N2 B21 u(f ) where the B21 is the coecient of stimulated emission, N2 is the number of atoms in the upper lever, u is the electromagnetic energy density. an
Wayne State University
Department of Physics and Astronomy
PHY 2131 General Physics
Experiment # 1
Measurements and Uncertain/es (I)
1.
Synopsis
You will learn how to estimate errors on measurements and how to use these estimat
Patrice Dodson
Section 0A1(Tuesday)
October 6, 2009
Newtons Second Law: The Atwood Machine
Purpose:
The purpose of this lab is to use Newtons Second Law to make an educated guess of the
acceleration of an Atwood machine. Then the guess will be used to ver
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Physics 118A
PROBLEM SET #2 Assigned: Wed. 1/23/08 Young & Freedman Chapters 22 & 23 Due Thur. 1/31/08 BOX YOUR FINAL ANSWERS. no later than 5:00 PM While we encourage discussion of the homework, each assignment is to be completed individually. Copy