Problem 4.10 In the circuit of Fig. P4.10, a bridge circuit is connected at the input side of an inverting op-amp circuit. (a) Obtain the Th venin equivalent at terminals (a, b) for the bridge circuit. e (b) Use the result in (a) to obtain an expression f
Sections 4-3 and 4-4: Ideal Op-Amp and Inverting Amp
Assume all op amps to be ideal from here on forward. Problem 4.9 The supply voltage of the op amp in the circuit of Fig. P4.9 is 16 V. If RL = 3 k, assign a resistance value to Rf so that the circuit wo
Problem 4.8 The op-amp circuit shown in Fig. P4.8 has a constant dc voltage of 6 V at the noninverting input. The inverting input is the sum of two voltage sources, a 6-V dc source and a small time-varying signal vs . (a) Use the op-amp equivalent-circuit
Problem 4.6 The inverting amplier circuit shown in Fig. P4.6 uses a resistor Rf to provide feedback from the output terminal to the inverting-input terminal. (a) Use the equivalent-circuit model of Fig. 4-4 to obtain an expression for the closed-loop gain
Problem 4.5 For the op-amp circuit shown in Fig. P4.5: (a) Use the model given in Fig. 4-4 to develop an expression for the current gain Gi = iL /is . (b) Simplify the expression by applying the ideal op-amp model by (taking A , Ri , and Ro 0).
vp vn is R
Problem 4.4 With its noninverting-input voltage at 10 V, the output voltage of an op amp is 15 V. If A = 5 105 and Vcc = 15 V, can you determine the magnitude of the inverting-input voltage? If not, can you determine its possible range? Solution: Since vo
Problem 4.2 An op amp with an open-loop gain of 6 105 and Vcc = 10 V has an output voltage of 3 V. If the voltage at the inverting input is 1 V, what is the magnitude of the noninverting-input voltage? Solution: vo = A(vp vn ) 3 = 6 105 (vp + 1 106 ) Henc
C HAPTER 3
Section 3-1: Node-Voltage Method
Problem 3.1 Apply nodal analysis to nd the node voltage V in the circuit of Fig. P3.1. Use the information to determine the current I .
V I 16 V + _ 2 3 2 + 4 _ 12 V
Figure P3.1: Circuit for Problem 3.1.
Solutio
Problem 2.45 Solution:
Repeat Problem 2.44 after replacing R with a short circuit.
4V _ 3 6 + + + 3 6
4V _
6
3
3
6
4V _ 2
I
63 6+3 =2
4 =1A 2+2 P = V I = 4 1 = 4 W. I=
Problem 2.41 Solution:
Find the power supplied by the generator in Fig. P2.41.
R1 = 18 1 20 V + _ 1 20 V + _ 18 1 20 V + _ 18 1 I 20 V + _ 9 6 6 6 18
Y 18 18
18
18
9 9
20 =2A 10 P = V I = 20 2 = 40 W. I=
Problem 2.36 For the circuit in Fig. P2.36, determine Req at (a) Terminals (a, b) (b) Terminals (a, c) (c) Terminals (a, d ) (d) Terminals (a, f )
e d c 2 2 2 2 2 a
Figure P2.36: Circuit for Problem 2.36.
f 2 2 2 2 2 b
Solution: All resistances are in ohm
Problem 2.27
For the circuit in Fig. P2.27, nd Ix for t < 0 and t > 0.
Ix + _ 2 t=0 1 2 3 4 4 4
15 V 2
Figure P2.27: Circuit with SPDT switch for Problem 2.27.
Solution: For t < 0:
Ix + _ 2 3 4 4 4
15 V 2
Ix + _
2 3
2 4
15 V 2
Ix + _
2 2 63 6 | 3 = 6 +
Problem 2.23 Determine the amount of power supplied by the independent current source in the circuit of Fig. P2.23.
+ V1 _ I 2 2
0.2 A
V1 4
Figure P2.23: Circuit for Problem 2.23.
Solution: KCL at top node gives 0.2 + Also I = V1 /2 (for the 2- resistor).
Problem 2.19
Determine Ix and Iy in the circuit of Fig. P2.19.
2 10 V + _ Ix I 4 6 Iy 4Ix + _
Figure P2.19: Circuit for Problem 2.19.
Solution: Application of KVL to the two loops gives 10 + 2Ix + 4I = 0 4I + 6Iy 4Ix = 0. Additionally, I = Ix Iy. Solution
Problem 2.3 A thin-lm resistor made of germanium is 2 mm in length and its rectangular cross section is 0.2 mm 1 mm, as shown in Fig. P2.3. Determine the resistance that an ohmmeter would measure if connected across its: (a) Top and bottom surfaces (b) Fr
Problem 1.21
The voltage across and current through a certain device are given by v(t ) = 5 cos(4 t ) V, i(t ) = 0.1 cos(4 t ) A.
Determine: (a) The instantaneous power p(t ) at t = 0 and t = 0.25 s. (b) The average power pav , dened as the average value
Problem 1.20 A 9-V ashlight battery has a rating of 1.8 kWh. If the bulb draws a current of 100 mA when lit, determine the following: (a) For how long will the ashlight provide illumination? (b) How much energy in joules is contained in the battery? (c) W
Problem 1.9 Determine the net charge Q that owed through a resistor over the specied time interval for each of the following currents: (a) i(t ) = 0.36 A, from t = 0 to t = 3 s (b) i(t ) = [40t + 8] mA, from t = 1 s to t = 12 s (c) i(t ) = 5 sin(4 t ) nA,
Problem 1.6 A certain cross section lies in the xy plane. If 3 1020 electrons go through the cross section in the z-direction in 4 seconds, and simultaneously, 1.5 1020 protons go through the same cross section in the negative z-direction, what is the mag
Name. EE 220 Circuits-I Quiz # 5- Solutions Spring Semester April 24, 2009 Maximum Points- 10
Time: 5 minutes 1. What is the meaning of steady-state condition of circuit?
circuit has reached to stable condition such that there is no variation in current o
Name. EE 220 Circuits-I Quiz # 3- Solutions Spring Semester March 11, 2009 Maximum Points- 10
Time: 5 minutes
1. Can we use the superposition method for nonlinear circuit elements? NO
2. How do we deactivate the independent current sources while using sup
Name. EE 220 CIRCUITS-I Quiz # 2 - Solutions Spring Semester February 25, 2009 Maximum Points- 10
Time: 5 minutes
1. Can we call two adjacent meshes having the combination of a current source in series with a resistor common to both the meshes as "superme
Name. EE 220 CIRCUITS-I Quiz # 1- Solutions Spring Semester February 6, 2009 Maximum Points- 10
Time: 5 minutes
1. Why is the direction of current flow opposite to the direction of electron flow? Due to Benjamin Franklin's reference the current is suppose
University of Nevada, Reno Department of Electrical and Biomedical Engineering
EE 220 L Circuits I Lab Spring 2009
Lab Room: SEM 346 Lab Hours:
Section 1 Monday Section 2 Tuesday Section 3 Wednesday Section 4 Thursday 2:30 - 5:15 pm 2:30 - 5:15 pm 2:30 -
EE 220L Spring 2009 Extra-Credit Quiz
Name: Work Independently! In specific technical terms, using laws we have already studied, EXPLAIN why the lights in your car momentarily dim when you start the engine. (Think of the electric starter motor and the lig