Knowing that = 25, determine the tension (a) in cable AC, (b) in rope BC.
Free-Body Diagram Force Triangle
Law of Sines: TAC T 5 kN = BC = sin115 sin 5 sin 60 (a) TAC = TBC = 5 kN sin115 = 5.23 kN sin 60 5 kN sin 5 = 0.503 kN
Two forces are applied to an eye bolt fastened to a beam. Determine graphically the magnitude and direction of their resultant using (a) the parallelogram law, (b) the triangle rule.
R = 8.4 kN
ES 201 Statics
ES 201 Statics Fall 2006
Tues. & Thurs., 8:00 - 9:20 a.m. Jones Annex 101 Instructor: Dr. T. David Burleigh, Associate Professor, Materials & Metallurgical Engineering Email: email@example.com, Phone: (505) 835-5831, Office: Jones Hall