Kelly Harrison 2/14/10 ST 558 D Homework 4 PROBLEM 1
Determine the value c so each of the following functions can serve as a probability distribution of the discrete random variable x.
a) f(x) = c(x2+4), x = 0, 1, 2, 3 f(x) = 1 c(02+4) + c(12+4) + c(22+4)

Kelly Harrison ST558 D 5/7/10 Homework #3 PROBLEM 1
According to a study published by a group of University of Massachusetts socio logists, approximately 60% of the Valiu m users in the state of Massachusetts first took Valium for psychological reasons.
n

Kelly Harrison ST 558D 2/1/10 Homework #2 PROBLEM 1 education elementary secondary college male 38 28 22 88 female 45 50 17 112 83 78 39 200
a) P(male | secondary) = 28/78 = 14/37 b) P(no college | female) = 1 17/112 = 95/112 PROBLEM 2 non-smokers hyperte

Kelly Harrison ST 558 Assignment 9
PROBLEM 1 96% z = 1.75
x
z/n = 780 1.75(40)/30 = (767.2, 792.8).
PROBLEM 2 a) n = 50, x = 174.5, s = 6.9 98% and df = 50 1 = 49 t = 2.407
x
ts/n = 174.5 2.405(6.9)/50 = (172.15, 176.85).
b) I would expect the error t

Kelly Harrison ST 558 PROBLEM 1 a)
P( x, y) = 1
x =0 y =0
* " . # B
C
2
4
x +y
x!y!
=C
-4
x ! y !
x =0 y =0
2 2
x
y
=C
x ! y !
x =0 y =0
2
x
2
y
= Ce e = Ce = 1
2 2 4
C =1/ e = e x
0 n
NOTE :
n!
= e
x
b)
P( x) = P( y) =
e
y =0
-4
2 2
x
y
x!y!
-4
= e = e

Kelly Harrison 2/21/10 ST 558 D Homework 5 PROBLEM 1 This is a Binomial Distribution with n = 3 and p = . = np = 3(1/4) = = .75 PROBLEM 2 x 0 1 2 3 4 P(x) 0.41 0.37 0.16 0.05 0.01 xP(x) 0 0.37 0.32 0.15 0.04 0.88 = xP(x) = .88 PROBLEM 3
In a gambling game