Solution 2
The Carnot Cycle:
Data Given:
Pa = 3 MPa ; Pc = 100 KPa ; Tc = 20 C = 20 + 273 = 293 K ;
Compression ratio = 15 = Vc/Va
(a) Thermal efficiency =
Now,
(b) Work output = thermal efficiency * Qh
Since process A to B is an isothermal process, hence
Solution to Problem 1:
(a) Since the actual work done here is against atmosphere hence it is an isobaric process and
Therefore,
Work done = p (V)
= 14.7 * (0.65 0.1)
= 8.085
(b) We know, Q = W + change n internal energy
Hence, U = Q W
Q is given to be .50
Solution to Problem 1:
(a) Since the actual work done here is against atmosphere hence it is an isobaric process and
Therefore,
Work done = p (V)
= 14.7 * (0.65 0.1)
= 8.085
(b) We know, Q = W + change n internal energy
Hence, U = Q W
Q is given to be .50