110000
150000
190000
200000
275000
275000
800000
Mean =
Median =
Mode =
#3
#2 Population- All patients of New York City hospitals
Sample: 1254 patients at New York City hospitals
Statistic: Hospitalization could have prevented in 25.8% of these 1254
cases

Probability Problems
Cassandra Rigney
1. In a lottery game, you pick one number from 000 to 999. If you pick one such number, what is the
probability that you will win the lottery?
P(1) x p(1000) = 1/1000 (0.1%)
2. 45% of all tourists who visit NYC go to

(data from US Census Bureau at census.gov)
State
Median
Income
Alabama
42,278
Alaska
67,629
Arizona
49,254
Arkansas
44,922
California
60,487
Colorado
60,940
Connecticut
70,161
Delaware
57,522
Florida
46,140
Georgia
49,555
Hawaii
71,223
Idaho
53,438
Illino

1
x = phones made
Profit/98%
0.98 * x * 150 = 147x
2% defective
0.02 * 300 * xx = 6x
Profit
(147-6)x = 141x
Profit probability is $141
If 2% are defective, then 98% are good.
2
x = profit per policy
1,000,000 * 800 = 800,000,000
annual profit
200,00 * 150

Company Name
(source at bottom . . )
Abercrombie & Fitch Co.
American Eagle Outfitters, Inc
Ascena Retail Group Inc.
Ashley (Laura) Holdings PLC
Bebe Stores, Inc.
Big Lots Inc.
Bon-Ton Stores Inc.
Boot Barn Holdings, Inc.
Burlington Stores, Inc.
Cherokee

'D
S.
?
-0")
9"i ,5. '=-
r
SvUQV
G\.,
Ip Is.' c:?" \.5i L O
%<[I
0'1') fJ
:>)<
7 <; )
'0 h
d
j
stL'O
qh
"
'\ - \
;:
\,.\
0
kbl:
19-\ -
.:c
5'2.
:.
o b"
(I
5,.'(/
J<
<:-
Q
-1./
8I
'tt>l"-
09A 1
: to hZ
0,
D
(tcl-
f)fh.tOI,l - (\11-
.-:;-; -A I'J L'o
L \ t

Cassandra Rigney
Test 2
1. Prof. Miller ran a marathon. Given that the mean finishing time for all runners was 255 minutes with a standard
deviation of 46 minutes and that finishing times were approximately normally distributed, find
(a) the percent of fi

Probability Answers
Prof. Miller
1
1. From 000 to 999, there are 1000 numbers. So, p(win) =
1000
2. p(ESB or SoL) = p(ESB) + p(SoL) - p(ESB and SoL) = 45% + 55% - 20% = 80%
3. A sock drawer contains five blue socks and eight black socks.
(a) a pair of bla

Statistics
Prof. Miller
Answers for Measures of Central Tendency and Dispersion
#1. Consider the data set: 70, 72, 84, 88, 90, 96, 96
x
(a)
2
n
=
7
x = 666 95.1, s
n
x -
=
59 6 2
7
2
n
64036
n 1
111.8095238,s
6
x
x -
2
=
7
n
51416
n 1
2
x
(b)
x = 596

Statistics
Solutions to Expected Value and Binomial
Prof. Miller
#1
Outcome
Profit/Loss
Probability
X * p(X)
Defective
-$300
0.02
-6
Non-defective
$150
0.98
147
Sum of X * p(X) =
$141
Outcome
#2
Probability p(x)
-700
0.2
-140
No accident
800
0.8
640
x p(x

Homework Assignment on Course Requirements
The purpose of this assignment is to ensure that you are able to submit assignments and that you have
read the syllabus.
#1 According to the syllabus, what is the best way of keeping track of the assignments that

Statistics Prof.Miller
1. Population: All overweight people
Parameter: Average weight loss for all overweight people who are treated with the drug, and
average weight loss for all overweight people who are given the placebo.
Sample: 321 overweight people

(data from US Census Bureau at census.gov dowloaded on September 8)
State
Median
Income
Alabama
41,381
Alaska
61,137
Arizona
50,602
Arkansas
39,919
California
57,528
Colorado
63,371
Connecticut
67,781
Delaware
52,219
Florida
47,886
Georgia
47,439
Hawaii
6

Cassandra Rigney
Normal Distribution
1. The gestation period (length of pregnancy) for male babies born in New York is
normally distributed with a mean of 39.4 weeks and a standard deviation of 2.43 weeks.
(a) What percent of mothers of male babies are pr