EE153 ENERGY CONVERSION
Assignment 3
Due: January 28, 2013 at 1:30pm NW201
1. A rectangular coil of sides 10cm by 5cm is rotated in a magnetic field of flux
density 1.5T where the longer sides cut the flux at 80 degrees. If the coil has 300
turns and rota
EE153 Lecture 13:
Introduction to Fluiddynamic Energy Conversion
Engr. Paulo E. Tindogan
1
References
http:/www.ustudy.in/node/3546
http:/ffden2.phys.uaf.edu/645spring2010_web.dir/srikamal/page3.htm
2
Outline
Introduction
Basic principles of MHD
Governing
EE153 ENERGY CONVERSION
Assignment 6
Due: February 18, 2014 at 1:30pm NW201
1. A coil which measures 30mm by 40mm carries a current of 200mA. The coil is
pivoted about an axis passing through the middle of the two shorter sides and is
placed in a uniform
LECTURE 7
DC generator losses:
1.Copper loss due to heat losses in the
armature and field windings
a. Armature copper loss = Ia2Ra
b. Shunt field copper loss = Ish2Rsh
c. Series field copper loss = Ise2Rse
Brush contact loss is included in armature
copper
MAPUA INSTITUTE OF TECHNOLOGY
INTRAMUROS, MANILA
EE153 ENERGY CONVERSION
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SCORE
EE153 ENERGY CONVERSION
Assignment 3
Due: January 28, 2013 at 1:30pm NW201
1. A rectangular coil of sides 10cm by 5cm is rotated in a magnetic field of flux
density 1.5T where the longer sides cut the flux at 80 degrees. If the coil has 300
turns and rota
EE153 Lecture 11:
Introduction to Thermoelectric Energy Conversion
Engr. Paulo E. Tindogan
1
References
http:/www.mhtl.uwaterloo.ca/Professional_Animation_Seebeck_File_HT
ML.html
http:/www.mpoweruk.com
http:/www.youtube.com/watch?v=21EC0lZ0imw
http:/www.y
Wind Power and Wind
Turbines
Engr. Paulo E. Tindogan
PPT prepared by:
BJ Furman
K Youssefi
Outline
Wind causes?
Wind Power example
Wind Turbine Design
Aerodynamics
Wind what causes it?
Atmospheric
pressure differences
~31 km
(99% of mass)
rth
Ea
Wher
LECTURE 2
DETERMINATION OF MAGNETIC FORCE AND
TORQUE FROM MAGNETIC FIELD ENERGY
Consider the magnetic circuit below:
The energy input to set up a flux (t) in an N-turn coil:
Where:
DETERMINATION OF MAGNETIC FORCE AND
TORQUE FROM MAGNETIC FIELD ENERGY
In a
LECTURE 5
EMF Equation for a DC Generator
Speed = N/60 rps. Therefore, time taken in one revolution is
60 / N
Total flux traversed by one conductor in one rotation,
P
P
NP
e
t 60 / N
60
As the armature has Z number of conductors, and there are A
number
EE153 ENERGY CONVERSION
Assignment 4
Due: February 4, 2014 at 1:30pm NW201
1. An 8-pole duplex wave DC generator has 50 slots, 2 coil sides per slots and 5
turns per coil. The pole shoe subtends an angle of 42 degrees. Its armature
diameter is 300 mm with
LECTURE 9
Force on a current-carrying conductor in a
magnetic field
The force depends upon:
Force on a current-carrying wire in a
magnetic field.
3
Flux compression and resulting
force.
4
e
Forc
Cu
rre
nt
M
ag
ne
tic
Fi
eld
Sample problems:
Principle of o
EE153 ENERGY CONVERSION
Assignment 5
Due: February 11, 2014 at 1:30pm NW201
1. A short-shunt dc generator delivers 200A at 500V. The resistances of the
armature, shunt, series, divertor, compensating winding and interpole are 0.02, 500,
0.02, 0.02, 0.01 a
EE153 ENERGY CONVERSION
Assignment 6
Due: February 18, 2014 at 1:30pm NW201
1. A coil which measures 30mm by 40mm carries a current of 200mA. The coil is
pivoted about an axis passing through the middle of the two shorter sides and is
placed in a uniform
