Amy Dowling
Alaskas History
Discussion Qs Ch 17,18,19
1. The three phases of economic development in Alaska, as defined by economist George W.
Rogers, were Native, Colonial, and Military Alaska. The N
Amy Dowling
Alaskas History
Discussion Questions Ch. 23,24,25
1. I think it was difficult for people in 1977 to imagine another bust cycle because Prudhoe Bay
was producing a lot of oil. Amid success,
Amy Dowling
Alaskas History
Discussion Questions Ch. 3,4,5
1. Ivan IV had given the responsibility of the defense of Russias eastern border and the Urals
region to a wealthy family called the Strogano
Amy Dowling
Alaskas History
News Article #1
Alaska needs to update its fisheries management, by Karl Johnstone and published in Alaska
Dispatch News on February 13, 2017, discusses the management of A
Amy Dowling
Alaskas History
Discussion Questions Ch. 11, 12, 13
1. The two main problems facing the salmon fisheries in the early 1900s were overfishing and the
monopolization of big companies over th
Amy Dowling
Alaskas History
Discussion questions Ch1-2
1.
2.
3.
4.
5.
6.
7.
I think that the author is saying that by studying the geology of Alaska we will have more
comprehensive understanding of th
Amy Dowling
Alaskas History
News Article #1
Alaska needs to update its fisheries management, by Karl Johnstone and published in Alaska
Dispatch News on February 13, 2017, discusses the management of A
Amy Dowling
Alaskas History
Ch. 6,7,8 Questions
1. Shelekov wanted to use the local Natives as labor to build up the Russian settlements. He
eventually wanted to incorporate these individuals into the
Amy Dowling
Alaskas History
Discussion Questions Ch. 20,21,22
1. The Omnibus Act of 1976 addressed the major issue of lands available for regional and village
corporation selections, specifically for
Amy Dowling
Alaskas History
Ch. 14,15,16 Discussion Questions
1. Military strategists recognized that concentrating military bases in a heartland, rather than
scattered about, made them much more easi
Amy Dowling
Alaskas History
Discussion Questions Ch. 26
1. I think that we are still facing a deficit because we are still relying on a non-renewable energy
source. People are still adamant about not
open interval (DF). Proof. (See Fig. 1.41.) By A 1.2.2 G
[DOG]. By L 1.2.1.3 aGD = aOD = h. Since F k, using
definition of (h, k) we conclude that F / h. By C
1.1.2.3 b (D b & G b & F b). Therefore DG
OBOAaOC OAOC aOC . Using the definition of the
interior of EOC, we have OAOEaOC & OAOC aOE OA
IntEOC. OA IntEOC & OC IntEOD L1.2.21.27
= OC IntAOD. Finally, OC IntAOD & OB
IntAOC L1.2.21.27 = OB Int
in its turn, adjacent supplementary to the angle (k, l).
Note also that, in a frequently encountered situation,
given an angle AOC such that the point O lies between
the point A and some other point B
Given an open interval (DB) having a point C on plane
aA and not meeting a line a Lemma 1.2.19.6. - If one of
the ends of (DB) lies in half-plane aA, the open interval
(DB) completely lies in half-pla
(usually) simply [ABC], 101 and say that the geometric
object B lies in the set J between the geometric objects A
and C, or that B divides A and C. 99By that lemma, any
open interval joining a point K
of generality. No loss of generality results from the fact
that the rays OA, OB, OC enter the conditions of the
theorem symmetrically. 109By A 1.1.3 E E a & E 6= O.
By A 1.1.2 a = aOE. By L 1.2.21.15,
parallel to lines a, c and has a point B b lying on an
open interval (AC), where A a, C c. Then the line b
lies completely inside ac. Proof. See L 1.2.19.16, L
1.2.19.20. Lemma 1.2.19.22. If a line b
(AB) also lies on the ray OC . Proof. By L 1.2.11.8 [OAB]
[OBA], whence by T 1.2.15 (AB) OA = OC . Given an
interval AB on a line aOC such that the open interval (AB)
does not contain O, we have (L 1
a line a, and B and C lie on opposite sides of the line a,
then A and C lie on the same side of a. Proof. (See Fig.
1.30.) AaB & BaC D (D a & [ADB]) & E (E a &
[BEC]) T1.2.6 = F (F a & [AF C]) ACa. 53
OD] [OAOBOD] & [OBOC OD]. The statements of this
theorem are easier to comprehend and prove when given
the following formulation in native terms. 1. If a ray OB
J lies inside an angle AOC, where OA,
direct order. For our notions of order (both direct and
inverse) on the set J to be well defined, they have to be
independent, at least to some extent, on the choice of
the origin O, as well as on the
arbitrary points A, O, B a and A , O , B b: If A O
on a and A O on b then points A, A lie on the same
side of the line aOO ; if O B on a and O B on b then
points B, B lie on the same side of the line
88Obviously, this means that given an angle (h, k),
none of the interior points of an angle (k, m) adjacent
to it, lies inside (h, k). 89The lemma L 1.2.21.15 is
applied here to every point of the ray
hypothesis that OA, OB form an angle. We conclude that
B / aOA, whence by C 1.1.2.3 b (A b & O b & B
b) and A / aOB. 71In practice the letter used to
denote the vertex of an angle is usually omitted
fact, since B aOA = b, we have either B OA or B
Oc A. L 1.2.19.8 then implies that in the first case B aA,
while in the second B a c A. Hence the result. Indeed,
suppose BAa, i.e. B aA. Then B OA, fo
suppose that : Nn1 Nn1 such that i, j, k
Nn1 (i < j < k) (k < j < i) [A(i)A(j)A(k) ]. By Pr 1.2.5,
L 1.2.22.13 [AnA(1)A(n1)] [A(1)A(n1)A(n) ] i i
Nn2 & [A(i)AnA(n+1)]. The values of are now
given fo
lying in on the same side of the line a as the point Q
106, admits a strong generalized betweenness relation.
To be more precise, we say that a ray OB J lies
between rays OA J and OC J iff OB lies ins
Lemma 1.2.19.3. A line b that is parallel to a line a and
has common points with a half-plane aA, lies
(completely) in aA. Proof. (See Fig. 1.31, a).) B aA B
aA. a & a aA & B & B aA A1.1.2
= aA. By
1.2.21.13, contradicts OC IntBOD. Lemma
1.2.21.30. Suppose that a finite sequence of points Ai,
where i Nn, n 3, has the property that every point of
the sequence, except for the first and the last, l