APPM 1340 Algebra Homework 3
Show all work.
1. Solve for x .
(x + 2)3/2 = 64
2. Solve the following system of equations for x and y .
6x 8y = 11
10x + 4y = 1
3. Solve the inequality
|3x + 5| 2.
Express the solution set in interval notation and graph on th

APPM 1340, Spring 2013: Final Exam
May 7, 2013
Instructions: Please show all of your work and make your methods and reasoning clear. Answers out
of the blue with no supporting work will receive no credit. No calculators, notes or electronic devices are
al

APPM 1340
Exam 2 Solutions
Fall 2011
There is a horizontal asymptote at y =
1.
(a)
2
lim
x 3
3
1
.
6
To nd candidates for vertical asymptotes, we set the denominator equal
to 0 and nd that 6x3 30x2 = 6x2 (x 5) = 0 when x = 0 or x = 5.
We evaluate lim g(x)

APPM 1340
Final Exam
Fall 2011
On the front of your bluebook, please write: a grading key, your name, student ID, section, and
instructors name (Chang or Nelson). This exam is worth 150 points and has 12 questions. Show all
work! Answers with no justicati

APPM 1340
Final Exam Solutions
sin
= lim
= 1.
0 sin
0
Fall 2011
(c) We use the theorem lim
cos 3x
1
x0
sin 3x sin 4x
x
x
= lim cos 3x
x0
sin 3x sin 4x
3x
4x
= lim cos 3x
x0
3 sin 3x 4 sin 4x
1
3x
1
4x
= lim cos 3x
x0
3 sin 3x 4 sin 4x
1
1
1
=1 1 1

APPM 1340
Exam 1
Fall 2011
On the front of your bluebook, please write: a grading key, your name, student ID, section, and
instructors name (Chang or Nelson). This exam is worth 100 points and has 9 questions. Show
all work! Answers with no justication wi

APPM 1340
Exam 1 Solutions
Fall 2011
(b) The perpendicular slope is the negative reciprocal of m.
m =
1. Consider two cases: 6x 3 9 and 6x 3 9.
1
= 3
m
Use the point-slope form to nd an equation of the perpendicular line.
Case 1:
y y1 = m(x x1 )
y 1 = 3(

APPM 1340
Exam 2
Fall 2011
On the front of your bluebook, please write: a grading key, your name, student ID, section, and
instructors name (Chang or Nelson). This exam is worth 100 points and has 8 questions. Show
all work! Answers with no justication wi

APPM 1340
Exam 3
Fall 2011
On the front of your bluebook, please write: a grading key, your name, student ID,
section, and instructors name (Chang or Nelson). This exam is worth 100 points and
has 5 questions. Show all work! Answers with no justication wi

APPM 1340
Exam 2
1 5(3) = 16 = 4. The slope of the
5
5
5
tangent line is f (3) =
= = .
8
2 16
2 1 5(3)
We use the point-slope form to nd an equation of the tangent line.
Fall 2010 Solutions
(b) At x = 3, f (3) =
1.
(a)
(b)
(c)
(d)
(e)
(0, 18), (40, 45)
t

APPM 1340
Exam 1
Fall 2010
INSTRUCTIONS: Books, notes, and electronic devices are not permitted. Write (1) your name,
(2) section number, and (3) a grading table on the front of your bluebook. Start each problem on
a new page. Simplify your answers. A cor

APPM 1340, Spring 2013: Exam 1
February 13, 2013
Instructions: Please show all of your work and make your methods and reasoning clear. Answers out
of the blue with no supporting work will receive no credit. No calculators, notes or electronic devices are

APPM 1340, Spring 2013: Exam 2
March 13, 2013
Instructions: Please show all of your work and make your methods and reasoning clear. Answers out
of the blue with no supporting work will receive no credit. No calculators, notes or electronic devices are
all

APPM 1340
1.
Final Exam Solutions
y = 3x + 3.
Fall 2010
(a) Use implicit differentiation to nd dy/dx.
2
(Problem inspired by the symbol described in Harry Potter and the Deathly
Hallows.)
2
x + y 2y = 0
dy
dy
2x + 2y
2
=0
dx
dx
dy
(2y 2) = 2x
dx
dy
2x
x
=

APPM 1340, Spring 2013: Exam 3
April 17, 2013
Instructions: Please show all of your work and make your methods and reasoning clear. Answers out
of the blue with no supporting work will receive no credit. No calculators, notes or electronic devices are
all

APPM 1340, Spring 2013: Exam 1
February 13, 2013
Instructions: Please show all of your work and make your methods and reasoning clear. Answers out
of the blue with no supporting work will receive no credit. No calculators, notes or electronic devices are

APPM 1340 Algebra Homework 4
Show all work.
1. Show that the lines
2x + 3y + 4 = 0
and
6x + 4y 12 = 0
are perpendicular. Find their point of intersection.
2. Consider the points P (6, 4) and Q(3, 1).
(a) Find an equation of the line that passes through P

APPM 1340 Course Syllabus.
Course website: http:/amath.colorado.edu/courses/1340/
WebAssign site: https:/www.webassign.net/colorado/login.html
Course Goals: To learn the concepts and techniques of differential and integral calculus; to learn to participat

APPM 1340
Exam 1
Fall 2012
On the front of your bluebook, please write: a grading key, your name, student ID, section, and instructors name (Chang or Dai). This exam is worth 100 points and has 10 questions. Show all work! Answers
with no justication will

APPM 1340
Exam 1 Solutions
Fall 2012
4. We are given the point (2, 1) and line 2x 4y = 3.
First rewrite the equation of the line in slope-intercept form.
2x 4y = 3
1.
(a) None . The function is dened for all values in the interval
2 x < 3.
4y = 2x + 3
1
y

APPM 1340
Exam 2
Fall 2012
On the front of your bluebook, please write: a grading key, your name, student ID, section, and
instructors name (Chang or Dai). This exam is worth 100 points and has 9 questions. Show all work!
Answers with no justication will

APPM 1340 Algebra Homework 1
Each of the following expressions has been evaluated incorrectly. Either provide the correct answer or
write Simplest form.
1. (x + 2)(x + 5) = x 2 + 10
2. (a + b)2 = a2 + b2
3.
7
7+x
=
3+x
3
4.
1
11
=+
y +6
y
6
5.
a/5
ab
=
b

APPM 1340 Algebra Homework 2
Solve for x in each of the following equations. Show all work.
1.
2x 2 3x 2 = 0
2.
3.
1
2
= 1
x 3 x +3
4
16
=
1
3
1
x
4.
5 + 2x 2 = 5
5.
(x 1)2 = 9
6.
x 3 + 3x 2 = 10x

APPM 1340
Exam 2 Study Guide
Fall 2013
Theorem
lim
0
sin
= lim
=1
0 sin
Strategies for Finding Limits
1. Simplify and try substitution.
Squeeze Theorem
2. Indeterminate Form (0/0).
(a) Factor and cancel.
(b) Multiply by a conjugate and cancel.
If f (x

APPM 1340
Exam 2
Fall 2013
On the front of your bluebook, please write: a grading key, your name, student ID, section, and instructors name. This exam is worth 100 points and has 7 questions. Show all work and simplify answers.
Answers with no justication

APPM 1340
Exam 1 Study Guide
Fall 2013
Point-slope equation of a line:
y = y1 + m(x x1 ).
A function f is a rule that assigns to each element x in a set D exactly
one element, called f (x), in a set R.
Slope-intercept equation of a line:
y = mx + b.
The s